Acetone is mixed with bleaching powder to give:
A. Chloroform
B. Acetaldehyde
C. Ethanol
D. Phosgene

Hint: Acetone is a methyl ketone, it has two methyl groups attached to carbonyl carbon. All the methyl ketones shows haloform tests.

Complete step-by-step answer: Haloalkane is the name of the compound created when a hydrogen atom is swapped out for an aliphatic hydrocarbon with a halogen atom. The halogen group is represented by $X$ in the haloalkane$(R - X)$.
Chloroform is produced when acetone combines with bleaching powder$(CaOC{l_2})$ in a haloform reaction. The response happens in the following three steps:
1. The bleaching powder breaks into calcium hydroxide and chlorine gas which are the main reagent of haloform test.
$(i)\,\,\,CaOC{l_2} + {H_2}O \to Ca{(OH)_2} + C{l_2} \\$

2. In the second step, $CC{l_3}COC{H_3}$ forms by the reaction of acetone and chlorine.
$(ii)\,\,\,C{H_3}COC{H_3} + 3C{l_2} \to CC{l_3}COC{H_3} + 3HCl \\$

3. In the third step, $CC{l_3}COC{H_3}$ hydrolysed to give chloroform and calcium salts of
carboxylic acids.
$(iii)\,\,\,2CC{l_3}COC{H_3}+ Ca{(OH)_2} \to 2CHCl_3 + 2CH_3COO^-+Ca^{2+}$

Therefore, Chloroform is created by combining acetone and bleaching powder.

Option ‘A’ is correct

Additional Information:The chemical molecule acetone, also known as propanone, or dimethyl ketone, has the formula${(C{H_3})_2}CO$. The smallest and most basic ketone. It is a colourless, incredibly combustible liquid with a distinctively strong smell.

Note: Aldehydes and ketones which have at least one methyl group linked to the carbonyl carbon atom are oxidised by bleaching powder to calcium salts of corresponding carboxylic acids having one carbon atom less than that of carbonyl compound. The methyl group is converted to haloform.