An air chamber having a volume V and a cross-sectional area of the neck is a into which a ball of mass m can move up and down without friction. Show that when the ball is pressed down a little and released, it executes SHM .Obtain an expression for the Time Period of oscillations assuming pressure –volume variations of air to be isothermal.

Answer
301.8k+ views
Hint: In the above given diagram it is given that the system is Isothermal that means the temperature in the whole system is assumed to be constant. Obtain the formula for the restoring force on the ball and the restoring force in simple harmonic motion. Compare both forces to obtain a time period of oscillations.
Complete step by step answer:
Let us consider the volume of the air chamber is $V$
Assume the area of cross-section of the neck is $a$
Also let the value of the Mass of the ball is $m$
The pressure inside the chamber is equal to the atmospheric pressure.
Let the ball be depressed by x units. As a result of this depression, there would be a decrease in the volume and an increase in the pressure inside the chamber.
Decrease in the volume of the air chamber, $\Delta V = ax$
Write the expression for the Bulk modulus of air.
$B = \dfrac{-p}{\dfrac{ax}{V}}$
In this case Stress is the increase in the pressure.
The negative sign indicates that it increases with decrease in Volume.
Now, write the expression for the pressure.
$P = \dfrac{-Bax}{V}$
The restoring force acting on the ball is calculated as,
$F = P \times a = \left( { - Bax/V} \right)\left( a \right) = - B{a^2}x/V$.........…. (i)
We know that in Simple Harmonic Motion, the equation for restoring force is written as
$F = - kx$.........…. (ii)
Where, $k$ is the spring constant.
Comparing equation (i) and (ii) we get,
$ - kx = - \dfrac{{B{a^2}x}}{V}$
$\Rightarrow k = \dfrac{B{a^2}}{V} $
Time period for the equation is,
$T = 2\pi \sqrt {\dfrac{m}{k}} $
Substitute the values of $k$ in the above equation to obtain,
$T = 2\pi \sqrt{\dfrac{mV}{B{a^2}}}$
Note: Do not confuse the negative sign mentioned in the expression. The negative sign indicates decrease in the volume and an increase in the pressure inside the chamber.
Complete step by step answer:
Let us consider the volume of the air chamber is $V$
Assume the area of cross-section of the neck is $a$
Also let the value of the Mass of the ball is $m$
The pressure inside the chamber is equal to the atmospheric pressure.
Let the ball be depressed by x units. As a result of this depression, there would be a decrease in the volume and an increase in the pressure inside the chamber.
Decrease in the volume of the air chamber, $\Delta V = ax$
Write the expression for the Bulk modulus of air.
$B = \dfrac{-p}{\dfrac{ax}{V}}$
In this case Stress is the increase in the pressure.
The negative sign indicates that it increases with decrease in Volume.
Now, write the expression for the pressure.
$P = \dfrac{-Bax}{V}$
The restoring force acting on the ball is calculated as,
$F = P \times a = \left( { - Bax/V} \right)\left( a \right) = - B{a^2}x/V$.........…. (i)
We know that in Simple Harmonic Motion, the equation for restoring force is written as
$F = - kx$.........…. (ii)
Where, $k$ is the spring constant.
Comparing equation (i) and (ii) we get,
$ - kx = - \dfrac{{B{a^2}x}}{V}$
$\Rightarrow k = \dfrac{B{a^2}}{V} $
Time period for the equation is,
$T = 2\pi \sqrt {\dfrac{m}{k}} $
Substitute the values of $k$ in the above equation to obtain,
$T = 2\pi \sqrt{\dfrac{mV}{B{a^2}}}$
Note: Do not confuse the negative sign mentioned in the expression. The negative sign indicates decrease in the volume and an increase in the pressure inside the chamber.
Recently Updated Pages
Four persons A B C and D initially at the corners of class 11 physics JEE_Main

What is the difference between Conduction and conv class 11 physics JEE_Main

Moment of inertia of solid sphere about its diameter class 11 physics JEE_Main

If a piece of ice floating on the surface of water class 11 physics JEE_Main

At what temperature speed of sound in air will be doubled class 11 physics JEE_Main

A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Understanding Uniform Acceleration in Physics

Other Pages
CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27 Free PDF Download (Sign-in Required)

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 3 Motion In A Plane - 2026-27 Free PDF Download (Sign-in Required)

