What is the angle between the pair of lines given by the equation ${x^2} + 2xy - {y^2} = 0$ ?
A. $\dfrac{\pi }{3}$
B. $\dfrac{\pi }{6}$
C. $\dfrac{\pi }{2}$
D. $0$
Answer
300k+ views
Hint: A pair of straight lines, passing through the origin, are represented by a general equation of the form $a{x^2} + 2hxy + b{y^2} = 0$ . Sum of the slopes of the two lines is given by $\dfrac{{ - 2h}}{b}$ and the product of the slopes is given by $\dfrac{a}{b}$ . The angle between the two lines, $\theta $ , is calculated using the formula $\tan \theta = \left| {\dfrac{{2\sqrt {{h^2} - ab} }}{{a + b}}} \right|$. Using this formula we will calculate the angle between both the lines.
Formula Used: The angle between a pair of straight lines, passing through the origin, represented by $a{x^2} + 2hxy + b{y^2} = 0$ is calculated using the formula $\tan \theta = \left| {\dfrac{{2\sqrt {{h^2} - ab} }}{{a + b}}} \right|$ .
Complete step-by-step solution:
Given equation of a pair of straight lines:
${x^2} + 2xy - {y^2} = 0$ … (1)
General form of a pair of straight lines passing through the origin:
$a{x^2} + 2hxy + b{y^2} = 0$ … (2)
Comparing equation (1) with the general form given in equation (2),
$a = 1$ ,
$b = - 1$ and
$h = 1$
Now, we know that the tangent of the angle, let’s say $\theta $ , between two lines is calculated using:
$\tan \theta = \left| {\dfrac{{2\sqrt {{h^2} - ab} }}{{a + b}}} \right|$
Substituting the values of the variables, we get:
$\tan \theta = \left| {\dfrac{{2\sqrt {1 - ( - 1)} }}{{1 + ( - 1)}}} \right|$
On simplifying further, we get:
$\tan \theta = \infty $
Calculating the inverse, we get $\theta = \dfrac{\pi }{2}$ .
Hence, the angle between the given lines is ${90^ \circ }$ .
Thus, the correct option is C.
Note: Compare the coefficients of the given equation to the general equation of a pair of straight lines properly. Then, substitute the corresponding values in the formula to calculate the tangent of the angle between the lines. Make sure to compare and substitute the values correctly to avoid any mistakes. We can directly find the angle between two lines using condition of perpendicular lines.
Formula Used: The angle between a pair of straight lines, passing through the origin, represented by $a{x^2} + 2hxy + b{y^2} = 0$ is calculated using the formula $\tan \theta = \left| {\dfrac{{2\sqrt {{h^2} - ab} }}{{a + b}}} \right|$ .
Complete step-by-step solution:
Given equation of a pair of straight lines:
${x^2} + 2xy - {y^2} = 0$ … (1)
General form of a pair of straight lines passing through the origin:
$a{x^2} + 2hxy + b{y^2} = 0$ … (2)
Comparing equation (1) with the general form given in equation (2),
$a = 1$ ,
$b = - 1$ and
$h = 1$
Now, we know that the tangent of the angle, let’s say $\theta $ , between two lines is calculated using:
$\tan \theta = \left| {\dfrac{{2\sqrt {{h^2} - ab} }}{{a + b}}} \right|$
Substituting the values of the variables, we get:
$\tan \theta = \left| {\dfrac{{2\sqrt {1 - ( - 1)} }}{{1 + ( - 1)}}} \right|$
On simplifying further, we get:
$\tan \theta = \infty $
Calculating the inverse, we get $\theta = \dfrac{\pi }{2}$ .
Hence, the angle between the given lines is ${90^ \circ }$ .
Thus, the correct option is C.
Note: Compare the coefficients of the given equation to the general equation of a pair of straight lines properly. Then, substitute the corresponding values in the formula to calculate the tangent of the angle between the lines. Make sure to compare and substitute the values correctly to avoid any mistakes. We can directly find the angle between two lines using condition of perpendicular lines.
Recently Updated Pages
If a parabola whose length of latus rectum is 4a touches class 11 maths JEE_Main

Find the cubic polynomial whose zeroes are 3 5 and class 11 maths JEE_Main

During the sale colour pencils were being sold in -class-11-maths-JEE_Main

A man on the top of a vertical observation tower o-class-11-maths-JEE_Main

In a class of 60 students 25 students play cricket class 11 maths JEE_Main

A regular polygon has 20 sides How many triangles can class 11 maths JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
NCERT Solutions For Class 11 Maths Chapter 6 Permutations And Combinations - 2026-27 Free PDF Download (Login Required)

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

NCERT Solutions For Class 11 Maths Chapter 9 Straight Lines - 2026-27 Free PDF Download (Sign-in Required)

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Maths Chapter 4 Complex Numbers And Quadratic Equations - 2026-27 Free PDF Download (Login Required)

Hybridisation in Chemistry – Concept, Types & Applications

