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At time $t = {t_1}$ an object’s velocity is given by the vector $\overrightarrow {{v_1}} $ shown below.
$ \to $
A short time later, at $t = {t_2}$, the object’s velocity is the vector $\overrightarrow {{v_2}} $
$ \nearrow $
If $\overrightarrow {{v_1}} $ and $\overrightarrow {{v_2}} $ have the same magnitude, which one of the following vectors best illustrates the object’s average acceleration between $t = {t_1}$ and $t = {t_2}$?
(A)
168飞艇 997763f1ba2de03563983368d0ca1fd5
(B)

168飞艇 7200da070f3dbf8d673e5b3b5d4b2bbb
(C)

168飞艇 f161de910bfe6cde1b34972aa8fe22a5
(D)

168飞艇 a830838678c78076f137a23fc832f693
(E)

168飞艇 78043900279a579dc9386e0225324d23

Answer
VerifiedVerified
302.1k+ views
Hint: Since the magnitudes of the vectors are the same so we need to only consider their direction. In order to calculate the acceleration, the direction of the first vector must be reversed to represent the difference.

Complete step by step answer
The basic difference between scalars and vectors is that scalar quantities just represent the magnitude whereas the vector represents both the direction and magnitude of the quantity.
For example, mass of a body does not have any particular direction but it does have a magnitude to represent the quantity. These types of quantities are called scalar quantities. On the other hand, the force acting on a body can be represented by both direction and magnitude. When we push someone or something, we are exerting some amount of force in a particular direction. These quantities are called vectors.
Vectors are usually denoted by drawing an arrow just above the sign representing the quantity.
In this question we need to find the resultant of two vectors.
We are given the velocity vectors at time ${t_1}$ and ${t_2}$
Now, acceleration is defined as the rate of change of velocity
So, $\overrightarrow a = \dfrac{{\overrightarrow {{v_2}} - \overrightarrow {{v_1}} }}{{{t_2} - {t_1}}}$
Now, the resultant of vectors $\overrightarrow {{v_1}} $ and $\overrightarrow {{v_2}} $results in option A. Since we need to find their difference, we can assume that the direction of vector $\overrightarrow {{v_1}} $ is reversed.
If this direction is reversed then their resultant vector would be correctly represented by option C.

Therefore, the correct option is C.

Note: Unlike scalar quantities, vectors have two types of product. Dot and cross. Dot product tells us how much of two vectors are in the same direction whereas the cross product tells us how little the two vectors are in the same direction. Dot product of two vectors gives us a scalar quantity, while the cross product of two vectors gives us a vector quantity.