The difference of the two angles in degree measure is 1 and their sum in radian measure is also 1. What are the angles in circular measure?
A. \[\left( {\dfrac{1}{2} - \dfrac{\pi }{{360}}} \right),\left( {\dfrac{1}{2} + \dfrac{\pi }{{360}}} \right)\]
B. \[\left( {\dfrac{1}{2} - \dfrac{{90}}{\pi }} \right),\left( {\dfrac{1}{2} + \dfrac{{90}}{\pi }} \right)\]
C. \[\left( {\dfrac{1}{2} - \dfrac{\pi }{{180}}} \right),\left( {\dfrac{1}{2} + \dfrac{\pi }{{180}}} \right)\]
D. None of these
Answer
300.3k+ views
Hint: Here, we will use when \[\alpha \] is an angle in degree measure then the relation between circular and degree measure is \[{\alpha ^C} = \dfrac{\pi }{{180}} \times \alpha \].
Apply this relation, and then use the given conditions to find the required value.
Complete step-by-step solution:
Given that the difference of the two angles in degree measure is 1 and their sum in radian measure is also 1.
Let us assume that the two angles are \[X\] and \[Y\] in degree measure.
We know that if \[\alpha \] is an angle in degree measure then the relation between circular and degree measure is \[{\alpha ^C} = \dfrac{\pi }{{180}} \times \alpha \].
First, we will find the equation representing the difference of the two angles in degree measure is 1.
\[X - Y = 1\]
But since the difference of the two angles is in degree measure, so we can write \[\dfrac{\pi }{{180}} = 1\].
Using this value of 1 in the above equation, we get
\[X - Y = \dfrac{\pi }{{180}}{\text{ ......}}\left( 1 \right)\]
We will now find the equation representing the sum of the two angles in radian measure is 1.
\[X + Y = 1{\text{ ......}}\left( 2 \right)\]
Subtracting the above equation by \[Y\] on each of the sides, we get
\[
\Rightarrow X + Y - Y = 1 - Y \\
\Rightarrow X = 1 - Y{\text{ .......}}\left( 3 \right) \\
\]
Substituting this value of \[X\] in the equation \[\left( 1 \right)\], we get
\[
\Rightarrow \left( {1 - Y} \right) - Y = \dfrac{\pi }{{180}} \\
\Rightarrow 1 - 2Y = \dfrac{\pi }{{180}} \\
\]
Subtracting the above equation by 1 on each of the sides, we get
\[
\Rightarrow 1 - 2Y - 1 = \dfrac{\pi }{{180}} - 1 \\
\Rightarrow - 2Y = \dfrac{\pi }{{180}} - 1 \\
\]
Dividing the above equation by \[ - 2\] on each of the sides, we get
\[
\Rightarrow \dfrac{{ - 2Y}}{{ - 2}} = \dfrac{1}{{ - 2}}\left( {\dfrac{\pi }{{180}} - 1} \right) \\
\Rightarrow Y = - \dfrac{\pi }{{360}} + \dfrac{1}{2} \\
\Rightarrow Y = \dfrac{1}{2} - \dfrac{\pi }{{360}} \\
\]
Substituting this value of \[Y\] in the equation \[\left( 3 \right)\], we get
\[
\Rightarrow X = 1 - \left( {\dfrac{1}{2} - \dfrac{\pi }{{360}}} \right) \\
\Rightarrow X = 1 - \dfrac{1}{2} + \dfrac{\pi }{{180}} \\
\Rightarrow X = \dfrac{1}{2} + \dfrac{\pi }{{360}} \\
\]
Therefore, the angles in circular measure are \[\dfrac{1}{2} + \dfrac{\pi }{{360}}\] and \[\dfrac{1}{2} - \dfrac{\pi }{{360}}\].
Hence, the option A is correct.
Note: In solving these types of questions, you should be familiar with the concept of circular measure and degree measures. Then use the given conditions and values given in the question, to find the required values. Also, we are supposed to write the values properly to avoid any miscalculation.
Apply this relation, and then use the given conditions to find the required value.
Complete step-by-step solution:
Given that the difference of the two angles in degree measure is 1 and their sum in radian measure is also 1.
Let us assume that the two angles are \[X\] and \[Y\] in degree measure.
We know that if \[\alpha \] is an angle in degree measure then the relation between circular and degree measure is \[{\alpha ^C} = \dfrac{\pi }{{180}} \times \alpha \].
First, we will find the equation representing the difference of the two angles in degree measure is 1.
\[X - Y = 1\]
But since the difference of the two angles is in degree measure, so we can write \[\dfrac{\pi }{{180}} = 1\].
Using this value of 1 in the above equation, we get
\[X - Y = \dfrac{\pi }{{180}}{\text{ ......}}\left( 1 \right)\]
We will now find the equation representing the sum of the two angles in radian measure is 1.
\[X + Y = 1{\text{ ......}}\left( 2 \right)\]
Subtracting the above equation by \[Y\] on each of the sides, we get
\[
\Rightarrow X + Y - Y = 1 - Y \\
\Rightarrow X = 1 - Y{\text{ .......}}\left( 3 \right) \\
\]
Substituting this value of \[X\] in the equation \[\left( 1 \right)\], we get
\[
\Rightarrow \left( {1 - Y} \right) - Y = \dfrac{\pi }{{180}} \\
\Rightarrow 1 - 2Y = \dfrac{\pi }{{180}} \\
\]
Subtracting the above equation by 1 on each of the sides, we get
\[
\Rightarrow 1 - 2Y - 1 = \dfrac{\pi }{{180}} - 1 \\
\Rightarrow - 2Y = \dfrac{\pi }{{180}} - 1 \\
\]
Dividing the above equation by \[ - 2\] on each of the sides, we get
\[
\Rightarrow \dfrac{{ - 2Y}}{{ - 2}} = \dfrac{1}{{ - 2}}\left( {\dfrac{\pi }{{180}} - 1} \right) \\
\Rightarrow Y = - \dfrac{\pi }{{360}} + \dfrac{1}{2} \\
\Rightarrow Y = \dfrac{1}{2} - \dfrac{\pi }{{360}} \\
\]
Substituting this value of \[Y\] in the equation \[\left( 3 \right)\], we get
\[
\Rightarrow X = 1 - \left( {\dfrac{1}{2} - \dfrac{\pi }{{360}}} \right) \\
\Rightarrow X = 1 - \dfrac{1}{2} + \dfrac{\pi }{{180}} \\
\Rightarrow X = \dfrac{1}{2} + \dfrac{\pi }{{360}} \\
\]
Therefore, the angles in circular measure are \[\dfrac{1}{2} + \dfrac{\pi }{{360}}\] and \[\dfrac{1}{2} - \dfrac{\pi }{{360}}\].
Hence, the option A is correct.
Note: In solving these types of questions, you should be familiar with the concept of circular measure and degree measures. Then use the given conditions and values given in the question, to find the required values. Also, we are supposed to write the values properly to avoid any miscalculation.
Recently Updated Pages
The HCF of two numbers is 96 and their LCM is 1296 class 10 maths JEE_Main

If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

Four persons A B C and D initially at the corners of class 11 physics JEE_Main

If a parabola whose length of latus rectum is 4a touches class 11 maths JEE_Main

Which of the following are correct regarding the normal class 13 maths JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

Trending doubts
JEE Main Marks vs Percentile 2026: Predict Your Score Easily

JEE Main Cutoff 2026: Category-wise Qualifying Percentile

JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marks vs Rank 2026: Expected Rank for 300 to 0 Marks

NIT Cutoff 2026: Tier-Wise Opening and Closing Ranks for B.Tech. Admission

JEE Mains 2027 Subject Wise Percentile Explained

Other Pages
CBSE Class 10 Maths Question Paper 2026 OUT Download PDF with Solutions

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions For Class 10 Maths Chapter 11 Areas Related To Circles - 2026-27 Free PDF Download (Login Required)

All Mensuration Formulas with Examples and Quick Revision

NCERT Solutions For Class 10 Maths Chapter 13 Statistics - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 10 Maths Chapter 14 Probability - 2026-27 Free PDF Download (Sign-in Required)

