The pressure exerted by a liquid column of height $h$ is given by (the symbols have their usual meanings).
(A) $\dfrac{h}{{\rho g}}$
(B) $h\rho g$
(C) $\dfrac{h}{\rho }$
(D) $hg$

Hint In these kinds of situations the first thing important is to notice the given problem statement. We can observe that this question though may seem twisted is perhaps a straight one. In this question we will get the answer simply by comparing the quantities by the basic definition of pressure.

Complete step by step answer:
Here, first we have to sort out the given quantities:
The height is given by: $h$
The density of the liquid is given by: $\rho $
And, the gravitational acceleration: $g$
Now, we clearly get that the pressure = $h\rho g$

Note Most important thing here is to notice the given values, then we can easily derive the answer by simple dimensional analysis. In these types of questions interpreting the correct methodology to be used is necessary unless it will get twisted.