A bag contains 100 tickets bearing numbers 1-100. A ticket is taken out randomly, find the probability of getting a ticket bearing a number which is the multiple of 25.
A. 0.5
B. 0.04
C. 1.0
D. 0.05

Hint: There are four numbers, which are multiple of 25, i.e. 25,50,75 and 100 from 1 to 100. The probability is the ratio of the favorable outcomes to the total number of outcomes. In this problem, the favorable outcome is multiples of 25 (25,50,75 and 100) that is 4, and the total outcome is 100.

Complete step by step answer:
Let, \[E\] be the Favorable outcomes which are multiple of 25. There are 4 tickets bearing numbers having multiples of 25 i.e. 25,50,75 and 100.
Therefore, \[n\left( E \right) = 4\]
Now, the probability of getting a ticket bearing a number having multiple of 25 is calculated as follows:
\[\begin{aligned}
  \,\,\,\,\,P\left( E \right) = \dfrac{{n\left( E \right)}}{{n\left( S \right)}} \\
   \Rightarrow P\left( E \right) = \dfrac{4}{{100}} \\
   \Rightarrow P\left( E \right) = \dfrac{1}{{25}} \\
   \Rightarrow P\left( E \right) = 0.04 \\
\end{aligned}\]

Thus, the probability of getting a ticket bearing a number having multiple of 25 is 0.04.

So, the correct answer is “Option B”.

Note: Probability of an event represents simply how likely something is to happen. In this problem, the probability is coming out to be 0.04, which shows that there is only a 4% chance to happen the given events. In general life many events cannot be predicted with complete certainty, hence we can use the probability to obtain the chance of happening the events.