A compound $X$ with molecular formula ${C_7}{H_8}$ is treated with $C{l_2}$ in presence of $FeC{l_3}$ .Which of the following compounds is formed during the reaction?
A)

B)

C)

D)

Hint:We need to remember that if a substituted aromatic compound is treated with an electrophile, it undergoes electrophilic aromatic substitution and gives a disubstituted compound which might be perceived utilizing the descriptors ortho, meta, and para. In the event that the overall yield of the ortho item and the para items are higher than that of the meta item, at that point the substituent inside the monosubstituted ring is named an ortho, para coordinating group.

Complete step by step answer:
We must remember that in the substituted aromatic compounds the group which is already attached on the ring influences the incoming group to the particular position and it is known as directive influence of the already attached group. Alkyl group is an ortho para directing group thus chlorine goes to the ortho and para position of the benzene ring.
Thus option A is correct.


Note:
We must remember that in the benzene ring the electron thickness is uniform at all carbon particles; consequently the assaulting electrophile has no special decision and may possess any position. Anyway in presence of a substituent the uniform electron thickness of benzene ring is upset and the core is either initiated or deactivated for additional replacement. For instance, if a methyl bunch is available in the core of benzene the sulphonation gets twenty to multiple times quicker under indistinguishable conditions. At the end of the day the presence of methyl bunch has initiated the core. Methyl bunch has impact and when methyl bunch is joining impact settles the creating positive charge and this brings down the actuation energy in the rate deciding advance bringing about the quicker response and the core is supposed to be enacted. Such gatherings which can deliver electrons into the core by inductive or reverberation impact, initiate the core.