A diamond weighs 3.71 g. It is put into a box weighing 1.4kg. Find the total weight of the box and diamond to the correct number of significant figures.
Answer
670.2k+ views
Hint: We need to add the given diamond mass and the mass of the box in the normal way and then find the value up to two significant digits by rounding the digits after the decimal point depending on the value of the digit if less or greater than 5.
Complete step-by-step answer:
Given the weight of the diamond = 3.71 g
We know the conversion between the grams and kilograms is 1kg = 1000g
So the value of the weight of the diamond in kgs becomes: 3.71 $\times10 ^{-3}$ = 0.00371 kg
Given Weight of the box = 1.4 kg
Therefore total weight = weight of the diamond + weight of the box
Now the value of the total weight in kgs becomes: 1.4 + 0.00371 = 1.40371 kg
Now we have found the value of the total weight in kgs so we get the value up to 2 significant digits by rounding the digits as 1.4 kg as the value after 4 is 0 which Is less than 5. So we have taken the number before 0 as it is.
So we have found the value of the total weight in kgs up to correct significant digits by
Hence the correct value of the weight of the total weight up to 2 significant digits is 1.4 kg
Additional information:
The correct number of the significant digits are found by taking the least number of significant digits present in the given numbers. For example, in the above problem, we have the number 1.4 kg which has the least number of significant digits equal to 2. Hence we need to find the sum or subtraction normally and then round off the digits up to the least number of the significant digits present in the given numbers.
Note: One of the possible mistakes that usually one tends to make in this kind of problem is that we take the number of significant digits as 3 thinking that 3.71 g has three significant digits and the answer goes wrong. We need to understand here that we need to take the correct number of significant digits as the least number of significant digits present in the given numbers after converting them into the same units.
Complete step-by-step answer:
Given the weight of the diamond = 3.71 g
We know the conversion between the grams and kilograms is 1kg = 1000g
So the value of the weight of the diamond in kgs becomes: 3.71 $\times10 ^{-3}$ = 0.00371 kg
Given Weight of the box = 1.4 kg
Therefore total weight = weight of the diamond + weight of the box
Now the value of the total weight in kgs becomes: 1.4 + 0.00371 = 1.40371 kg
Now we have found the value of the total weight in kgs so we get the value up to 2 significant digits by rounding the digits as 1.4 kg as the value after 4 is 0 which Is less than 5. So we have taken the number before 0 as it is.
So we have found the value of the total weight in kgs up to correct significant digits by
Hence the correct value of the weight of the total weight up to 2 significant digits is 1.4 kg
Additional information:
The correct number of the significant digits are found by taking the least number of significant digits present in the given numbers. For example, in the above problem, we have the number 1.4 kg which has the least number of significant digits equal to 2. Hence we need to find the sum or subtraction normally and then round off the digits up to the least number of the significant digits present in the given numbers.
Note: One of the possible mistakes that usually one tends to make in this kind of problem is that we take the number of significant digits as 3 thinking that 3.71 g has three significant digits and the answer goes wrong. We need to understand here that we need to take the correct number of significant digits as the least number of significant digits present in the given numbers after converting them into the same units.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

