A man sitting on a beach watching water waves sees 4 waves pass by in 2 seconds, each with a wavelength of \[0.5\,{\text{m}}\]. Find out the speed of the waves.
A. \[0.25\,{\text{m/s}}\]
B. \[0.5\,{\text{m/s}}\]
C. \[1.0\,{\text{m/s}}\]
D. \[2.0\,{\text{m/s}}\]
E. \[4.0\,{\text{m/s}}\]
Answer
629.7k+ views
Hint: Use the formula for frequency of the wave. This formula gives the relation between the frequency of the wave, number of waves and time. Also use the formula for the velocity of the wave. This formula gives the relation between the velocity of the wave, frequency of the wave and wavelength of the wave. First calculate the frequency of the wave and then calculate the speed of the wave.
Formulae used:
The frequency \[n\] of a wave is given by
\[n = \dfrac{N}{t}\] …… (1)
Here, \[N\] is the number of complete cycles of the wave and \[t\] is the time.
The speed \[v\] of a wave is given by
\[v = n\lambda \] …… (2)
Here, \[n\] is frequency of the wave and \[\lambda \] is wavelength of the wave.
Complete step by step answer:
We have given that the man sitting on the beach watches 4 waves in 2 seconds.Hence, the number of complete waves 4 in time 2 seconds.
\[N = 4\]
\[\Rightarrow t = 2\,{\text{s}}\]
The wavelength of the wave seen by the man is \[0.5\,{\text{m}}\].
\[\lambda = 0.5\,{\text{m}}\]
Let us first calculate the frequency of the waves seen by the man.
Substitute 2 for \[N\] and \[2\,{\text{s}}\] for \[t\] in equation (1).
\[n = \dfrac{4}{{2\,{\text{s}}}}\]
\[ \Rightarrow n = 2\,{{\text{s}}^{ - 1}}\]
Hence, the frequency of the waves seen by the man is \[2\,{{\text{s}}^{ - 1}}\].
Let us now calculate the speed of the waves seen by the man.
Substitute \[2\,{{\text{s}}^{ - 1}}\] for \[n\] and \[0.5\,{\text{m}}\] for \[\lambda \] in equation (2).
\[v = \left( {2\,{{\text{s}}^{ - 1}}} \right)\left( {0.5\,{\text{m}}} \right)\]
\[ \therefore v = 1.0\,{\text{m/s}}\]
Therefore, the speed of the wave is \[1.0\,{\text{m/s}}\].
Hence, the correct option is C.
Note: The students should be careful while determining the frequency and speed of the waves seen by the man. Also the students should keep in mind that the frequency of the wave is shown by different symbols. So, the students should not get confused between these different signs. Any of the variables used to denote the frequency can be used.
Formulae used:
The frequency \[n\] of a wave is given by
\[n = \dfrac{N}{t}\] …… (1)
Here, \[N\] is the number of complete cycles of the wave and \[t\] is the time.
The speed \[v\] of a wave is given by
\[v = n\lambda \] …… (2)
Here, \[n\] is frequency of the wave and \[\lambda \] is wavelength of the wave.
Complete step by step answer:
We have given that the man sitting on the beach watches 4 waves in 2 seconds.Hence, the number of complete waves 4 in time 2 seconds.
\[N = 4\]
\[\Rightarrow t = 2\,{\text{s}}\]
The wavelength of the wave seen by the man is \[0.5\,{\text{m}}\].
\[\lambda = 0.5\,{\text{m}}\]
Let us first calculate the frequency of the waves seen by the man.
Substitute 2 for \[N\] and \[2\,{\text{s}}\] for \[t\] in equation (1).
\[n = \dfrac{4}{{2\,{\text{s}}}}\]
\[ \Rightarrow n = 2\,{{\text{s}}^{ - 1}}\]
Hence, the frequency of the waves seen by the man is \[2\,{{\text{s}}^{ - 1}}\].
Let us now calculate the speed of the waves seen by the man.
Substitute \[2\,{{\text{s}}^{ - 1}}\] for \[n\] and \[0.5\,{\text{m}}\] for \[\lambda \] in equation (2).
\[v = \left( {2\,{{\text{s}}^{ - 1}}} \right)\left( {0.5\,{\text{m}}} \right)\]
\[ \therefore v = 1.0\,{\text{m/s}}\]
Therefore, the speed of the wave is \[1.0\,{\text{m/s}}\].
Hence, the correct option is C.
Note: The students should be careful while determining the frequency and speed of the waves seen by the man. Also the students should keep in mind that the frequency of the wave is shown by different symbols. So, the students should not get confused between these different signs. Any of the variables used to denote the frequency can be used.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

