A particle performing UCM changes its angular velocity from $70\,\,r.p.m$ to $130\,r.p.m$ in$18\, s$. Find the angular acceleration of the particle. (In $\dfrac {rad} {{{s} ^ {2}}} $)
(A)$0.36$
(B)$0.349$
(C)$0.69$
(D)$0.48$
Answer
598.8k+ views
Hint: This question involves the concept of uniform circular motion. In this question, we will first convert initial and final angular velocities from r.p.m. to r.p.s. then, we will calculate the final and initial angular velocity. After finding this, we will calculate the ratio of the difference between initial angular velocity and final angular velocity to the time taken. Now, we will apply the formula of angular velocity to calculate angular acceleration of the particle.
Complete step by step answer:
We have already been given the angular velocity expression so let us assume,
${{\omega} _ {1}} $ = initial angular velocity,
${{\omega} _ {2}} $ = final angular velocity
Now, we will convert the given frequencies from r.p.m. to r.p.s. –
Initial frequency,${{f}_{1}}=\,\dfrac{70}{60}r.p.s.$
Final frequency,${{f}_{2}}=\dfrac{130}{60}r.p.s.$
For calculation of angular velocity we use formula,
$\omega =2\pi f$ where, $f$ = frequency
${{\omega} _ {1}} =2\pi {{f} _ {1}} =2\pi \dfrac{70}{60}=\dfrac{7}{3}\dfrac{rad}{s}$
${{\omega} _ {2}} =2\pi {{f} _ {2}} =2\pi \dfrac{130}{60}=\dfrac{13}{3}\dfrac{rad}{s}$
As we know the basic formula of angular velocity so, by applying below expression we get value of angular acceleration:${{\omega }_{t}}={{\omega }_{0}}+\alpha t$ where,
${{\omega} _ {t}} $ = final angular velocity,
${{\omega} _ {0}} $ =initial angular velocity,
$\alpha $ =angular acceleration.
$\begin {align}
& \therefore {{\omega} _ {2}} = {{\omega} _ {1}} +\alpha t \\
& \Rightarrow \alpha =\dfrac {{{\omega} _ {2}}-{{\omega} _ {1}}} {t} \\
& \Rightarrow \alpha =\dfrac {\dfrac{13}{3}-\dfrac{7}{3}}{18} \\
& \Rightarrow \alpha =0.349\dfrac {rad} {{{s} ^ {2}}} \\
& \\
\end{align}$
So, the correct answer is “Option B”.
Note: Angular acceleration is a vector quantity which gives both magnitude and direction. Angular momentum is defined as the vector quantity which is used to measure the rotational momentum of the body or system in rotation. This angular momentum is equal to the product of the angular velocity of the system or body and its moment of inertia with respect to the rotation axis and, this is directed along the rotational axis in classical physics. We must revise the unit of the quantity because we may create mistakes in the unit of angular velocity and angular acceleration.
Complete step by step answer:
We have already been given the angular velocity expression so let us assume,
${{\omega} _ {1}} $ = initial angular velocity,
${{\omega} _ {2}} $ = final angular velocity
Now, we will convert the given frequencies from r.p.m. to r.p.s. –
Initial frequency,${{f}_{1}}=\,\dfrac{70}{60}r.p.s.$
Final frequency,${{f}_{2}}=\dfrac{130}{60}r.p.s.$
For calculation of angular velocity we use formula,
$\omega =2\pi f$ where, $f$ = frequency
${{\omega} _ {1}} =2\pi {{f} _ {1}} =2\pi \dfrac{70}{60}=\dfrac{7}{3}\dfrac{rad}{s}$
${{\omega} _ {2}} =2\pi {{f} _ {2}} =2\pi \dfrac{130}{60}=\dfrac{13}{3}\dfrac{rad}{s}$
As we know the basic formula of angular velocity so, by applying below expression we get value of angular acceleration:${{\omega }_{t}}={{\omega }_{0}}+\alpha t$ where,
${{\omega} _ {t}} $ = final angular velocity,
${{\omega} _ {0}} $ =initial angular velocity,
$\alpha $ =angular acceleration.
$\begin {align}
& \therefore {{\omega} _ {2}} = {{\omega} _ {1}} +\alpha t \\
& \Rightarrow \alpha =\dfrac {{{\omega} _ {2}}-{{\omega} _ {1}}} {t} \\
& \Rightarrow \alpha =\dfrac {\dfrac{13}{3}-\dfrac{7}{3}}{18} \\
& \Rightarrow \alpha =0.349\dfrac {rad} {{{s} ^ {2}}} \\
& \\
\end{align}$
So, the correct answer is “Option B”.
Note: Angular acceleration is a vector quantity which gives both magnitude and direction. Angular momentum is defined as the vector quantity which is used to measure the rotational momentum of the body or system in rotation. This angular momentum is equal to the product of the angular velocity of the system or body and its moment of inertia with respect to the rotation axis and, this is directed along the rotational axis in classical physics. We must revise the unit of the quantity because we may create mistakes in the unit of angular velocity and angular acceleration.
Recently Updated Pages
Difference Between Prokaryotic Cells and Eukaryotic Cells

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

