A person has a high fever and has a temperature of 315K. This temperature on Fahrenheit scale is?

Hint: We usually measure temperature for fever in Fahrenheit. When we say the temperature of a person is 101, we are taking in Fahrenheit. Here, we have given temperature in Kelvin so we have to find it in Fahrenheit.

Complete step by step answer:
${T_{(F)}} = {T_{(K)}} \times \dfrac{9}{5} - 459.67$
Where:
${T_{(F)}}$= Temperature in Fahrenheit.
${T_{(K)}}$= Temperature in Kelvin (315K).

Complete Solution Step by Step:-
Put the given value of temperature in Kelvin and find out the temperature in Fahrenheit
${T_{(F)}} = {T_{(K)}} \times \dfrac{9}{5} - 459.67$;
Put the value of the given temperature in Kelvin in the above equation
${T_{(F)}} = 315K \times \dfrac{9}{5} - 459.67$;
Solve for the temperature in Fahrenheit${T_F}$ ,
$
  {T_{(F)}} = 567 - 459.67 = 107.3F \\
    \\
 $
Final Answer: The temperature in Fahrenheit is$107.3F$.
Additional Information: Temperature is a physical quantity that was essentially used to measure heat. There are three basic measuring units of temperature namely Fahrenheit, Kelvin, Celsius. The scientists use Kelvin as a unit for measuring temperature. Fahrenheit and Celsius are used in common households. Temperature is a relative measurement that is dependent upon many variables. That is one of the reasons for the temperature having 3 units.

Note: There is another method of converting Kelvin into Fahrenheit.
First convert Kelvin into Fahrenheit and then convert it into Celsius.
${T_k} - 273.15 = {T_c}$
Put the value in the above equation and solve for ${T_c}$.
$315 - 273.15 = {41.85^ \circ }C$
And then convert it into Fahrenheit.
$({T_C} \times \dfrac{9}{5}) + 32 = {T_F}$
Put the value and solve for ${T_F}$
$(41.85 \times \dfrac{9}{5}) + 32 = {T_F}$
${T_F} = 107.33F$
Also note,here the temperature is given in Kelvin, to convert it into Fahrenheit we have to apply a formula that converts Kelvin into Fahrenheit. Apply the formula and make sure there is no mathematical/calculation error while solving the formula.