What is a solubility product? Establish the relation between solubility and solubility product for CdS type compounds. In third group analysis, \[N{H_4}Cl\] is added before \[N{H_4}OH\], Why?
Answer
585.9k+ views
Hint: A solid, liquid, or gaseous chemical compound ability to dissolve in a solvent (usually a liquid) and form a solution is known as solubility. A substance's solubility is largely determined by the solvent used, as well as temperature and pressure.
Complete answer:
Solubility Product:
It is defined as the product of the ion concentrations in a saturated electrolyte solution at a given temperature. The symbol \[{K_{sp}}\] is used to represent it.
As salt is dissolved in a solvent, the interactions between ions and the solvent must counteract the strong forces of attraction of the solute (lattice enthalpy of the ions).
Ions have a negative solvation enthalpy, which ensures that energy is released during the process.
The nature of the solvent determines the amount of energy released during solvation that is solvation enthalpy.
The solvation enthalpy of non-polar solvents is low, indicating that this energy is insufficient to resolve the lattice enthalpy.
As a result, non-polar solvents cannot dissolve the salts. As a result, a salt's solvation enthalpy must be greater than its lattice enthalpy in order for it to dissolve in a solvent.
For CdS form compounds, there is a relationship between solubility and solubility products.
Let x be the CdS solubility.
\[{\mathbf{CdS}} \rightleftharpoons {\mathbf{C}}{{\mathbf{d}}^{2 + }} + {{\mathbf{S}}^{\mathbf{2}}}\]
\[{{\mathbf{K}}_{{\text{sp}}}} = \left[ {{\mathbf{C}}{{\mathbf{d}}^{2 + }}} \right]\left[ {{{\mathbf{S}}^{2 - }}} \right]\]
\[{{\mathbf{K}}_{{\text{sp}}}} = = ({\text{x}}) \times ({\text{x}})\]
\[{{\mathbf{K}}_{{\text{sp}}}} = {{\mathbf{x}}^2}\]
B.
Since the \[N{H_4}^ + \] ions supplied by \[N{H_4}Cl\]lower the ionisation of \[N{H_4}OH\] and hence the concentration of \[O{H^ - }\] ion in the third group study, \[N{H_4}Cl\] is added before \[N{H_4}OH\]. Hydroxides of the III group form at low \[O{H^ - }\] ion concentrations. The precipitation of group hydroxides occurs when \[N{H_4}OH\] is added in the presence of \[N{H_4}Cl\].
Note:
The description of the cation and anion of an inorganic salt is known as salt analysis (also known as systematic qualitative analysis or qualitative inorganic analysis). This may be accomplished by defining the cation and anion of the salt separately.
Complete answer:
Solubility Product:
It is defined as the product of the ion concentrations in a saturated electrolyte solution at a given temperature. The symbol \[{K_{sp}}\] is used to represent it.
As salt is dissolved in a solvent, the interactions between ions and the solvent must counteract the strong forces of attraction of the solute (lattice enthalpy of the ions).
Ions have a negative solvation enthalpy, which ensures that energy is released during the process.
The nature of the solvent determines the amount of energy released during solvation that is solvation enthalpy.
The solvation enthalpy of non-polar solvents is low, indicating that this energy is insufficient to resolve the lattice enthalpy.
As a result, non-polar solvents cannot dissolve the salts. As a result, a salt's solvation enthalpy must be greater than its lattice enthalpy in order for it to dissolve in a solvent.
For CdS form compounds, there is a relationship between solubility and solubility products.
Let x be the CdS solubility.
\[{\mathbf{CdS}} \rightleftharpoons {\mathbf{C}}{{\mathbf{d}}^{2 + }} + {{\mathbf{S}}^{\mathbf{2}}}\]
\[{{\mathbf{K}}_{{\text{sp}}}} = \left[ {{\mathbf{C}}{{\mathbf{d}}^{2 + }}} \right]\left[ {{{\mathbf{S}}^{2 - }}} \right]\]
\[{{\mathbf{K}}_{{\text{sp}}}} = = ({\text{x}}) \times ({\text{x}})\]
\[{{\mathbf{K}}_{{\text{sp}}}} = {{\mathbf{x}}^2}\]
B.
Since the \[N{H_4}^ + \] ions supplied by \[N{H_4}Cl\]lower the ionisation of \[N{H_4}OH\] and hence the concentration of \[O{H^ - }\] ion in the third group study, \[N{H_4}Cl\] is added before \[N{H_4}OH\]. Hydroxides of the III group form at low \[O{H^ - }\] ion concentrations. The precipitation of group hydroxides occurs when \[N{H_4}OH\] is added in the presence of \[N{H_4}Cl\].
Note:
The description of the cation and anion of an inorganic salt is known as salt analysis (also known as systematic qualitative analysis or qualitative inorganic analysis). This may be accomplished by defining the cation and anion of the salt separately.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

