$AgCl + NH_{ 4 }OH \rightarrow $ ……………..
This question has multiple correct options.
(A) $NH_{ 4 }Cl$
(B) $Ag(NH_{ 3 })_{ 2 }Cl$
(C) $H_{ 2 }O$
(D) AgCl

Hint: One of the compounds formed in this reaction is a complex compound. You can easily identify that in the options. Also, $NH_{ 4 }OH$ can be written as a mixture of ammonia and water. Now try to answer it accordingly.

Complete step by step answer:

The reaction between AgCl and $NH_{ 4 }OH$ will result in the products of $Ag(NH_{ 3 })_{ 2 }^{ + }$ and ${ Cl }^{ - }$ ions.
The reason is that basically when you have a container that has NH₄OH in it, you basically don’t have ammonium ions $NH_{ 4 }^{ + }$ and ${ OH }^{ - }$ ions as we are used to, instead, you have $NH_{ 3 }$ and some water in there because ammonium hydroxide is not very stable to stay that way, that is why those $NH_{ 3 }$ molecules will react with AgCl to make a complex of $Ag(NH_{ 3 })_{ 2 }^{ + }$ with some ${ Cl }^{ - }$ ions as products.
Hence, we can say Silver chloride reacts with ammonium hydroxide to produce diamminesilverchloride and water.
$AgCl + 2 NH_{ 4 }OH \rightarrow Ag(NH_{ 3 })_{ 2 }Cl + 2 H_{ 2 }O$

Therefore, we can conclude that the correct answers to this question are options B and C.

Note: This is "silver diammine" and not "silver diamine". There are two of the letters "m". "Amine" refers to the $-NH_{ 2 }$ group. If it contains ammonia, then "ammine" has two m's.
Silver Ammonium Chloride - This is a complex compound and considered not to be a True salt. This is also not a very stable product, and it will revert back to initial reactants (AgCl) and ammonia will be given off as a gas.