At ${27^ \circ }{\text{C}}$, $195{\text{ ml}}$ of a gas are collected in a graduated tube over ${\text{Hg}}$. When barometer reads the reading equal to $745{\text{ mm}}$, the level of inside the tube is $60{\text{ mm}}$ above the outside ${\text{Hg}}$ level. Calculate volume of gas at STP.
A) $160{\text{ ml}}$
B) $130{\text{ ml}}$
C) $180{\text{ ml}}$
D) ${\text{210 ml}}$
Answer
618.6k+ views
Hint:We are given that the level of mercury in the tube is $60{\text{ mm}}$ above the outside mercury level and the barometer reading is $745{\text{ mm}}$. To find the level of mercury in the tube, subtract the given level from the barometer reading.
Complete step-by-step solution:
We will first calculate the level of mercury in the tube. To find the level of mercury in the tube, subtract the given level from the barometer reading. The level in the tube is the measurement of pressure. Thus,
${P_1} = \left( {745 - 60} \right){\text{ mm}}$
${P_1} = 685{\text{ mm}}$
Thus, the volume of the gas is $685{\text{ mm}}$.
The temperature given is ${27^ \circ }{\text{C}}$. Thus,
${T_1} = {27^ \circ }{\text{C}} + 273$
${T_1} = 300{\text{ K}}$
And the volume of the gas is ${V_1} = 195{\text{ ml}}$.
We have to calculate the volume of gas at STP i.e. standard temperature and pressure.
The standard temperature and pressure means the temperature is $298{\text{ K}}$ and the pressure is $1{\text{ atm}}$.
Thus, ${T_2} = 273{\text{ K}}$ and ${P_2} = 1{\text{ atm}} = 760{\text{ mm}}$.
We know the ideal gas equation is,
$PV = nRT$
Where, $P$ is the pressure of the ideal gas,
$V$ is the volume of the ideal gas,
$n$ is the number of moles of ideal gas,
$R$ is the universal gas constant,
$T$ is the temperature of the gas.
Thus,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
${V_2} = \dfrac{{{P_1}{V_1}{T_2}}}{{{T_1}{P_2}}}$
${V_2} = \dfrac{{685{\text{ mm}} \times 195{\text{ ml}} \times 273{\text{ K}}}}{{{\text{300 K}} \times 760{\text{ mm}}}}$
${V_2} = 159.93{\text{ ml}} = 160{\text{ ml}}$
Thus, the volume of gas at STP is $160{\text{ ml}}$.
Thus, the correct option is (A), $160{\text{ ml}}$.
Note:Ideal gas is a hypothetical gas. The ideal gas molecules do not attract or repel each other. The ideal gas law states that the pressure, temperature and the volume of a gas are related to each other. The interaction between molecules of an ideal gas is elastic collision or elastic collision with the container walls.
Complete step-by-step solution:
We will first calculate the level of mercury in the tube. To find the level of mercury in the tube, subtract the given level from the barometer reading. The level in the tube is the measurement of pressure. Thus,
${P_1} = \left( {745 - 60} \right){\text{ mm}}$
${P_1} = 685{\text{ mm}}$
Thus, the volume of the gas is $685{\text{ mm}}$.
The temperature given is ${27^ \circ }{\text{C}}$. Thus,
${T_1} = {27^ \circ }{\text{C}} + 273$
${T_1} = 300{\text{ K}}$
And the volume of the gas is ${V_1} = 195{\text{ ml}}$.
We have to calculate the volume of gas at STP i.e. standard temperature and pressure.
The standard temperature and pressure means the temperature is $298{\text{ K}}$ and the pressure is $1{\text{ atm}}$.
Thus, ${T_2} = 273{\text{ K}}$ and ${P_2} = 1{\text{ atm}} = 760{\text{ mm}}$.
We know the ideal gas equation is,
$PV = nRT$
Where, $P$ is the pressure of the ideal gas,
$V$ is the volume of the ideal gas,
$n$ is the number of moles of ideal gas,
$R$ is the universal gas constant,
$T$ is the temperature of the gas.
Thus,
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
${V_2} = \dfrac{{{P_1}{V_1}{T_2}}}{{{T_1}{P_2}}}$
${V_2} = \dfrac{{685{\text{ mm}} \times 195{\text{ ml}} \times 273{\text{ K}}}}{{{\text{300 K}} \times 760{\text{ mm}}}}$
${V_2} = 159.93{\text{ ml}} = 160{\text{ ml}}$
Thus, the volume of gas at STP is $160{\text{ ml}}$.
Thus, the correct option is (A), $160{\text{ ml}}$.
Note:Ideal gas is a hypothetical gas. The ideal gas molecules do not attract or repel each other. The ideal gas law states that the pressure, temperature and the volume of a gas are related to each other. The interaction between molecules of an ideal gas is elastic collision or elastic collision with the container walls.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

