Change these numbers into special numbers
(i) 28
(ii) 132

Hint: According to the question firstly proceed with the given number by taking its reverse. Then adding both of the numbers to check if the sum is a special number or not if it is not a special number then we will continue with the repeated process.

Complete step-by-step answer:
Here we will follow simple methodology to find the special numbers in both of the parts.
(a)Let's take a given number that is 28, now rotate it in the reverse order. So, we get the reverse number that is 82. Then add both of the original number as well as reversed number: \[28{\rm{ }} + {\rm{ }}82{\rm{ }} = {\rm{ }}110\] . As the obtained number is not a special number because when we reverse its order, we get 011. So, now again we will add both of the obtained number as well as its reverse: \[110{\rm{ }} + {\rm{ }}011{\rm{ }} = {\rm{ }}121\] .Now when we reverse its order, we get 121 which is equal to obtained number. So we can say that 121 is a special number.

(b)Let's take a given next number that is 132, now rotate it in the reverse order. So, we get the reverse number that is 231. Then add both of the original number as well as reversed number: \[132{\rm{ }} + {\rm{ }}231{\rm{ }} = {\rm{ }}363\] Now when we reverse its order, we get 363 which is equal to obtained number. So we can say that 363 is a special number.

Note: To solve these types of questions we must know the definition of the special number that is a number which is equal to the converted reverse order of that number. For example 121 is a special number as its reverse number is also equal to 121.