Consider the following distribution of daily wages of a factory.
Daily wages (in Rs.) 500 – 520 520 – 540 540 – 560 560 – 580 580 – 560 Number of workers 12 14 8 6 10
Find the mean daily wages of the workers of the factory by using the appropriate method.
| Daily wages (in Rs.) | 500 – 520 | 520 – 540 | 540 – 560 | 560 – 580 | 580 – 560 |
| Number of workers | 12 | 14 | 8 | 6 | 10 |
Answer
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Hint: Here we are given the daily wages and number of workers falling in that range. To find mean we will directly use a formula to find mean. But we also have to find the middle value of the daily wages range. This middle value acts as a representative of the other frequencies falling in that class.
Complete step-by-step solution:
Now we will use the direct method for calculation. Let’s tabulate the data.
The middle value or class mark of a frequency range is given by,
Mid-value $ = \dfrac{{upper\,limit + lower\,limit}}{2}$
The frequency table is,
We know that the general formula to find the mean value is,
Mean $ = \dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{x_i}} }}$
Now, we will substitute the value for the sum of the product of frequency and midpoint and the value for the sum of total frequency.
$ \Rightarrow $ Mean $ = \dfrac{{27260}}{{50}}$
Divide numerator by the denominator,
$\therefore $ Mean $ = 545.2$
Hence the daily wages of workers is $545.2$.
Note: Here in this problem data given of classes are in grouped form. No direct numbers are given so do find the middle values or class mark of the range. And then proceed for calculations. Always tabulate these types of problems.
In the mean formula, while computing $\sum {fx} $, don’t take the sum of $f$ and $x$ separately and then multiply them. It will be difficult. Students should carefully make the frequency distribution table; there are high chances of making mistakes while copying and computing data.
Complete step-by-step solution:
Now we will use the direct method for calculation. Let’s tabulate the data.
The middle value or class mark of a frequency range is given by,
Mid-value $ = \dfrac{{upper\,limit + lower\,limit}}{2}$
The frequency table is,
| Daily Expense | No. of households (${f_i}$) | Mid value (${x_i}$) | ${f_i}{x_i}$ |
| 500 – 520 | 12 | 510 | 6120 |
| 520 – 540 | 14 | 530 | 7420 |
| 540 – 560 | 8 | 550 | 4400 |
| 560 – 580 | 6 | 570 | 3420 |
| 580 – 600 | 10 | 590 | 5900 |
| Total | $\sum {{f_i}} = 50$ | $\sum {{f_i}{x_i}} = 27260$ |
We know that the general formula to find the mean value is,
Mean $ = \dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{x_i}} }}$
Now, we will substitute the value for the sum of the product of frequency and midpoint and the value for the sum of total frequency.
$ \Rightarrow $ Mean $ = \dfrac{{27260}}{{50}}$
Divide numerator by the denominator,
$\therefore $ Mean $ = 545.2$
Hence the daily wages of workers is $545.2$.
Note: Here in this problem data given of classes are in grouped form. No direct numbers are given so do find the middle values or class mark of the range. And then proceed for calculations. Always tabulate these types of problems.
In the mean formula, while computing $\sum {fx} $, don’t take the sum of $f$ and $x$ separately and then multiply them. It will be difficult. Students should carefully make the frequency distribution table; there are high chances of making mistakes while copying and computing data.
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