Construct a ROSE in kite in which RO = 4.5cm, OS = 5.4cm, and one of the diagonals RS = 7.7cm. (Hint: Kite is a quadrilateral with two pairs of adjacent sides equal)
Answer
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Hint: For solving this question you should know about the quadrilateral or a shape of the kite. In this problem first we will draw a line RO and make the line OS with this and then we will make the diagonal RS. This diagonal will make this as a triangle. And then we will copy the same sides opposite to each other and will make another triangle with the same measurements but mirrored shape on the same base RS. And thus we will get our diagram ROSE.
Complete step by step answer:
According to the question it is asked to make a kite ROSE with the given dimensions. For solving this, we will use the following steps:
Step 1: Draw a line RO whose length is 4.5cm.
Step 2: From the point O draw an arc of 5.4cm and also from the point R and arc of 7.7cm, both intersecting at S. So, the rough diagram for that is:
Step 3: From point R another arc is drawn of 4.5cm and from point S of 5.4cm. Both intersect at a point E. Draw lines from all points give the quadrilateral ROSE.
So if we make the final diagram for this with all the dimensions then it will be:
Note: Students have to be precise while drawing the lengths and angles properly as this is a crucial part of the problem. A minor mistake in drawing can lead to the wrong solution. It is always recommended to understand the process.
Complete step by step answer:
According to the question it is asked to make a kite ROSE with the given dimensions. For solving this, we will use the following steps:
Step 1: Draw a line RO whose length is 4.5cm.
Step 2: From the point O draw an arc of 5.4cm and also from the point R and arc of 7.7cm, both intersecting at S. So, the rough diagram for that is:
Step 3: From point R another arc is drawn of 4.5cm and from point S of 5.4cm. Both intersect at a point E. Draw lines from all points give the quadrilateral ROSE.
So if we make the final diagram for this with all the dimensions then it will be:
Note: Students have to be precise while drawing the lengths and angles properly as this is a crucial part of the problem. A minor mistake in drawing can lead to the wrong solution. It is always recommended to understand the process.
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