How do you convert 0.47(47 being repeated) to a fraction?
Answer
627k+ views
Hint:In the above given question we have to convert the decimal number with the same numbers repeated after it into fraction. We can do this by using a formula to convert from decimal to fraction in which of repeated number size should be known.
Complete step by step solution:
Given is the decimal fraction that is 0.47. It is mentioned that 47 is repeated after the decimal point.
Hence, we can say that 0.47 is a repeating decimal number. Here repeating decimal number can be represented as:\[0.\overline {47} \].
A bar is added above 47 since both the numbers are repeated. For example, if only 7 was repeated then the bar would have only been on 7 denoting that only 7 is repeating.
The formula for converting the repeated decimal number to fraction is given below:
\[\dfrac{{(DN \times F) - NRP}}{D}\]
where DN stands for decimal number.
F stands 100 if repeating number is of size 2
NRP stands for Non-repeating part of decimal number.
D is 99 if the repeating number is of size 2.
Therefore, by substituting the values we get,
Since,\[0.\overline {47} \] is repeating as a fraction we get
\[
\dfrac{{(0.47 \times 100) - 0}}{{99}} \\
= \dfrac{{47}}{{99}} \\
\]
Hence, we get the above answer in the form of fraction.
Note: An important part to note is that the non-repeating number here is 0 because it is the only number which is not repeating. For example, if only 7 was repeating after the decimal point then the non-repeating part from 0.47 will be 0.4.
Complete step by step solution:
Given is the decimal fraction that is 0.47. It is mentioned that 47 is repeated after the decimal point.
Hence, we can say that 0.47 is a repeating decimal number. Here repeating decimal number can be represented as:\[0.\overline {47} \].
A bar is added above 47 since both the numbers are repeated. For example, if only 7 was repeated then the bar would have only been on 7 denoting that only 7 is repeating.
The formula for converting the repeated decimal number to fraction is given below:
\[\dfrac{{(DN \times F) - NRP}}{D}\]
where DN stands for decimal number.
F stands 100 if repeating number is of size 2
NRP stands for Non-repeating part of decimal number.
D is 99 if the repeating number is of size 2.
Therefore, by substituting the values we get,
Since,\[0.\overline {47} \] is repeating as a fraction we get
\[
\dfrac{{(0.47 \times 100) - 0}}{{99}} \\
= \dfrac{{47}}{{99}} \\
\]
Hence, we get the above answer in the form of fraction.
Note: An important part to note is that the non-repeating number here is 0 because it is the only number which is not repeating. For example, if only 7 was repeating after the decimal point then the non-repeating part from 0.47 will be 0.4.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

