How do I create a linear equation with a given solution like $ (3,0) $ ?
Answer
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Hint: Here in this question, we have to create linear equation using a given point, to create linear equation use the equation of the line, which intersects the y-axis at a point is given by: \[y = mx + b\], Where, b is the intercept, m is the slope of the line and y and x indicate the points on y-axis and x-axis respectively. On substituting we get the required solution.
Complete step by step solution:
Linear equations are equations of the first order. These equations are defined for lines in the coordinate system. An equation for a straight line is called a linear equation. The general representation of the straight-line equation is \[y = mx + b\] where, m is the slope of the line and b is the y-intercept.
Now, we have to create a linear equation with a given solution of point $ (3,0) $ . Which means the line must pass through the point $ (3,0) $ . In other words, we can say that we need to find a slope and y-intercept so that the equation \[y = mx + b\] will only work when $ (x,y) = (3,0) $ .
Now, we substitute these values in the equation \[y = mx + b\] .
$ \Rightarrow y = mx + b $
$ \Rightarrow 0 = m(3) + b $
Now, we will solve for the value of $ b $ i.e., y-intercept
$ \Rightarrow \,\,b = - 3m $
On substituting, y-intercept $ b $
Then, the equation will be,
$ \Rightarrow y = mx - 3m $
Take \[m\] as common
$ \Rightarrow y = m(x - 3) $
Ending with an equation like this that links \[b\] and \[m\] means that there are an infinite number of slope-intercept pairs that produce a line that passes through $ (3,0) $ .
Hence, there are infinitely many such linear equations. Choose any \[b\] or \[m\] and plug it into \[b = - 3m\] to get the other. Your equation will be \[y = mx + b\] with these values of \[m\] and \[b\] .
So, the correct answer is “ y = m(x - 3)”.
Note: The general or standard representation of the straight-line equation is \[Ax + By = C\], it involves only a constant term and a first-order (linear) term. While shifting or transforming the term in the equation we should take care of the sign. Here sign conventions are used in this problem.
Complete step by step solution:
Linear equations are equations of the first order. These equations are defined for lines in the coordinate system. An equation for a straight line is called a linear equation. The general representation of the straight-line equation is \[y = mx + b\] where, m is the slope of the line and b is the y-intercept.
Now, we have to create a linear equation with a given solution of point $ (3,0) $ . Which means the line must pass through the point $ (3,0) $ . In other words, we can say that we need to find a slope and y-intercept so that the equation \[y = mx + b\] will only work when $ (x,y) = (3,0) $ .
Now, we substitute these values in the equation \[y = mx + b\] .
$ \Rightarrow y = mx + b $
$ \Rightarrow 0 = m(3) + b $
Now, we will solve for the value of $ b $ i.e., y-intercept
$ \Rightarrow \,\,b = - 3m $
On substituting, y-intercept $ b $
Then, the equation will be,
$ \Rightarrow y = mx - 3m $
Take \[m\] as common
$ \Rightarrow y = m(x - 3) $
Ending with an equation like this that links \[b\] and \[m\] means that there are an infinite number of slope-intercept pairs that produce a line that passes through $ (3,0) $ .
Hence, there are infinitely many such linear equations. Choose any \[b\] or \[m\] and plug it into \[b = - 3m\] to get the other. Your equation will be \[y = mx + b\] with these values of \[m\] and \[b\] .
So, the correct answer is “ y = m(x - 3)”.
Note: The general or standard representation of the straight-line equation is \[Ax + By = C\], it involves only a constant term and a first-order (linear) term. While shifting or transforming the term in the equation we should take care of the sign. Here sign conventions are used in this problem.
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