David has d books which is three times as many as Jeff and $\dfrac{1}{2}$ as much as Paula how many books the three of them have in terms of d ?
A) $\dfrac{5}{6}d$
B) $\dfrac{7}{3}d$
C) $\dfrac{{10}}{3}d$
D) $\dfrac{7}{2}d$
E) $\dfrac{9}{2}d$

Hint: Using variables to represent how many books David, Jeff, and Paula have. Express the given conditions in the form of equations and equating both. Then we have to determine in terms of d , the sum of the number of books that David, Jeff and Paula have altogether.

Complete step-by-step answer:
Let the no. of books Jeff has be j and the no. of books Paula be p .
Now according to the question,
$d = 3 \times j$
$ \Rightarrow j = \dfrac{d}{3}$
And
$d = \dfrac{1}{2} \times p$
$ \Rightarrow p = 2d$
Now total no. of books all three of them have = d + j + p
=$d + \dfrac{d}{3} + 2d = \dfrac{{3d + d + 6d}}{3} = \dfrac{{10d}}{3}$

Note: To solve these types of questions we should equate the given values accurately to get the result. Calculations while solving such questions should be done at last to avoid confusion.