Define the following:-
(i)Angle of projection
(ii)Velocity of projection
(iii)Trajectory

Hint- To solve this problem you need to consider the motion of a particle projected at some angle in the presence of gravitational force. Knowing this will solve your problem.

Complete step-by-step answer:
Angle p in the figure is the angle of projection. The horizontal velocity u is always constant since there is no acceleration in x direction. The path OQX is the trajectory of motion. H is the maximum height of the particle when it undergoes this motion.

(i) Angle of projection - It is the angle with the surface with which the projectile is projected. The maximum range angle of the projectile should be 45⁰. This application is used for various purposes to send the particle to maximum distance.

(ii) Velocity of projection – It is the velocity with which the projectile is projected. Velocity of projection largely determined the various aspects of the projectile such as time of flight, range, etc.

(iii) Trajectory – It is the path followed by the projectile after it has been projected.



Note - The basic principles and assumptions of the subject should be understood in these queries. All three terms are commonly used in projectile motion in which the particle’s trajectory is parabolic. Knowing this will solve your problem and we advise students to learn the derivation of various formulas for range, maximum height, time period etc. Since sometimes it asks to derive the formulas for different arrangements in which the acceleration is in both x and y axis. So, knowing the basics will help you to get the formulas in any arrangements as well.