How can I draw the Lewis structure for NO?

Hint Lewis dot structures also known as electron dot structures. Lewis dot structures represent the valence electrons of the atoms present within the molecule. By Lewis dot structures we can visualize the bonding electrons and lone pair of electrons present in the molecule.

Complete answer:
- In the question it is asked to draw the Lewis structure of the NO molecule.
- We know that the atomic number of oxygen is 8 and has eight electrons in its electronic configuration.
- The electronic configuration of oxygen is $1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}$
- So oxygen has six valence electrons in 2s and 2p orbital.
- The Lewis dot structure of the beryllium is as follows.

- Coming to Nitrogen, the atomic number of nitrogen element is 7 and its electronic configuration is $1{{s}^{2}}2{{s}^{2}}2{{p}^{3}}$ and has five valence electrons in its electronic configuration.
- The Lewis dot structure of nitrogen is as follows.

- Now by taking the above structures as examples we can draw the Lewis dot structure of NO and it is as follows.

- From the above Lewis dot structure we can easily say that an oxygen atom has two lone pairs of electrons and nitrogen has one lone pair of electrons and one single electron in NO molecule.

Note: By using Lewis dot structures of the molecules we can determine the formation of the chemical bonds in various molecules. We can draw the Lewis dot structures for the compounds containing covalent bonds and also we can draw for coordination compounds.