How do you evaluate $\dfrac{{99}}{3} \times 6 \times 8\left( 9 \right)$ ?

Hint: We don’t have to worry about the BODMAS rule here. We can either do multiplication or division first. First, we will divide $6$ by $3$. Then we will multiply all the terms remaining $99$. Then we will write $99$ as $\left( {100 - 1} \right)$ for further evaluation.

Complete step-by-step answer:
In this question, we do not have to worry about the order of operation because multiplication and division are equally strong.
We will do it in a different way without using any calculator.
We could divide $99$ by $3$. But we would choose not to.
Multiplying by $99$ is very close to multiplying by $100$, so leave $99$ as it is.
$ = \dfrac{{99}}{3} \times 6 \times 8\left( 9 \right)$
Now divide $6$ by $3$, we get $2$.
$ = 99 \times 2 \times 8\left( 9 \right)$
Now we will multiply $8\,with\,9\,to\,get\,72$.
$ = 99 \times 2 \times 72$
Now, multiplying $2\,with\,72$.
$ = 99 \times 144$
We can also write it as $99 = \left( {100 - 1} \right)$ using distributive property.
$ = \left( {100 - 1} \right) \times 144$
On multiplication, we get
$ = 14400 - 144$
We can also as, $144 = 100 + 44$
$ = 14400 - 100 - 44$
$ = 14300 - 44$
On subtracting, we get
$ = 14256$

Note: We can simplify any equation without a calculator. We can break down both the numerator (top number) and denominator (bottom number) into their prime factors. Cross out any common factors. Multiply the remaining numbers to get the reduced numerator and denominator.