Factorize: \[9{{x}^{2}}-3x-20\]
Answer
586.5k+ views
Hint: We are given a quadratic equation and we are asked to factorize the equation which is given in terms of ‘x’. The given equation is of the form, \[a{{x}^{2}}+bx+c\]. So, we will be splitting the mid-term in order to factorize the quadratic equation. The mid-term should be split up such that the product of the split terms should be equal to \[ac\] and their sum should be equal to \[b\]. As per our equation, the product is equal to -180 and their sum should be equal to -3, so we get our terms as -15 and 12. We will split up the middle term and get the common terms out. Hence, we will have factorized the given quadratic equation.
Complete step by step answer:
According to the given question, we are given a quadratic equation and we are asked to factorize the equation.
The equation that we have is,
\[9{{x}^{2}}-3x-20\]
We can see that the given equation is of the form \[a{{x}^{2}}+bx+c\].
We will use the splitting middle term technique to factorize the equation.
The middle term should be such that the product of the terms should be equal to \[ac=-180\] and the sum should be equal to \[b=-3\]
So, we can find it as,
\[\begin{align}
& 180\times 1 \\
& 90\times 2 \\
& 45\times 4 \\
& 15\times 12 \\
\end{align}\]
That is, we can have the split terms as -15 and 12 as it follows the given condition.
So, we have,
\[\Rightarrow 9{{x}^{2}}+(-15x+12x)-20\]
\[\Rightarrow 9{{x}^{2}}-15x+12x-20\]
Now, we will pair up the terms and take the common terms out and we get the new expression as,
\[\Rightarrow 3x(3x-5)+4(3x-5)\]
Now, taking the common bracket out, we get,
\[\Rightarrow (3x+4)(3x-5)\]
Therefore, the factorization of the given quadratic equation is \[(3x+4)(3x-5)\].
Note: The factorization should be carried out step wise without missing any terms. Also, pay attention to the signs of each of the terms in the given equation, as it is of significance during the process of factorization. The terms to be used while splitting up the middle term should be carefully found and with appropriate signs.
Complete step by step answer:
According to the given question, we are given a quadratic equation and we are asked to factorize the equation.
The equation that we have is,
\[9{{x}^{2}}-3x-20\]
We can see that the given equation is of the form \[a{{x}^{2}}+bx+c\].
We will use the splitting middle term technique to factorize the equation.
The middle term should be such that the product of the terms should be equal to \[ac=-180\] and the sum should be equal to \[b=-3\]
So, we can find it as,
\[\begin{align}
& 180\times 1 \\
& 90\times 2 \\
& 45\times 4 \\
& 15\times 12 \\
\end{align}\]
That is, we can have the split terms as -15 and 12 as it follows the given condition.
So, we have,
\[\Rightarrow 9{{x}^{2}}+(-15x+12x)-20\]
\[\Rightarrow 9{{x}^{2}}-15x+12x-20\]
Now, we will pair up the terms and take the common terms out and we get the new expression as,
\[\Rightarrow 3x(3x-5)+4(3x-5)\]
Now, taking the common bracket out, we get,
\[\Rightarrow (3x+4)(3x-5)\]
Therefore, the factorization of the given quadratic equation is \[(3x+4)(3x-5)\].
Note: The factorization should be carried out step wise without missing any terms. Also, pay attention to the signs of each of the terms in the given equation, as it is of significance during the process of factorization. The terms to be used while splitting up the middle term should be carefully found and with appropriate signs.
Recently Updated Pages
What are the two major island groups in India class 9 social science CBSE

What is Jhum cultivation class 9 biology CBSE

Write an Article on Save Earth Save Life

Silk is obtained from of the silk moth APupa BLarva class 9 chemistry CBSE

Write chemical formulas of the following compounds class 9 chemistry CBSE

The Indo Gangetic Plains of India are fertile due to class 9 social science CBSE

Trending doubts
Who was referred to as Amitraghata by the Greeks AChandragupta class 9 social science CBSE

On an outline map of India show its neighbouring c class 9 social science CBSE

Differentiate between parenchyma collenchyma and sclerenchyma class 9 biology CBSE

Distinguish between Khadar and Bhangar class 9 social science CBSE

The normal temperature of the human body on the Kelvin class 9 biology CBSE

Air is a A Homogenous mixture B Heterogeneous mixture class 9 chemistry CBSE


