Find $\dfrac{11}{3}$ in its mixed fraction from.

Hint: We first try to explain the improper fraction and the representation in mixed fraction. We use variables to express the condition between those representations.Then we apply long division to express the improper fraction in mixed fraction.

Complete step by step answer:
We need to convert it into a mixed fraction which is a representation in the form sum of an integer and a proper fraction. We express the process in the form of variables. Let the fraction be $\dfrac{a}{b}$ where $a>b$. Now we express it in the form of a mixed fraction.Let’s assume the integer we get is $x$ and the proper fraction is $\dfrac{c}{b}$.

Then the equational condition will be $\dfrac{a}{b}=x+\dfrac{c}{b}$. The representation of the mixed fraction will be $x\dfrac{c}{b}$.The solution of the equation
$x+\dfrac{c}{b}=\dfrac{bx+c}{b}$.
This means $\dfrac{a}{b}=\dfrac{bx+c}{b}$. Therefore, the final condition for the fraction will be $a=bx+c$.

Now we solve our fraction $\dfrac{11}{3}$. We express it in a regular long division process. The denominator is the divisor. The numerator is the dividend. The quotient will be the integer of the mixed fraction. The remainder will be the numerator of the proper fraction.
$3\overset{3}{\overline{\left){\begin{align}
  & 11 \\
 & \underline{9} \\
 & 2 \\
\end{align}}\right.}}$
Therefore, the proper fraction is $\dfrac{2}{3}$. The integer is 3.

The simplified representation of the fraction $\dfrac{11}{3}$ is $3\dfrac{2}{3}$.

Note: We need to remember that the denominator in both cases of improper fraction and the mixed fraction will be the same. The only change happens in the numerator. The relation being the equational representation of $a=bx+c$.