Find the probability of getting a tail when an unbiased coin is tossed.
A. 0
B. $\dfrac{1}{2}$
C. 1
D. 2

Hint: We first explain the concept of probability and how the events are considered. We take the given events and find the number of outcomes. Using the probability theorem of $P\left( A \right)=\dfrac{n\left( A \right)}{n\left( U \right)}$, we get the probability of the event of coin tossing.

Complete step by step answer:
Empirical probability uses the number of occurrences of an outcome within a sample set as a basis for determining the probability of that outcome.We take two events, one with conditions and other one without conditions. The later one is called the universal event which chooses all possible options. We find the number of outcomes for both events. We take the conditional event A and the universal event as U and numbers will be denoted as $n\left( A \right)$ and $n\left( U \right)$.

We take the probability of the given problem as
$P\left( A \right)=\dfrac{n\left( A \right)}{n\left( U \right)}$
We are given that an unbiased coin is tossed and we need to find the probability of getting a tail. The possible number of outcomes for tossing a coin is either Head or Tail. Therefore, if the condition of getting a tail is considered as A, then
$n\left( A \right)=1$ and $n\left( U \right)=2$.
The probability of the shooting event is $P\left( A \right)=\dfrac{1}{2}$.

Hence, the correct option is B.

Note: We need to understand the concept of universal events. This will be as the main event that is implemented before the conditional event. Empirical probabilities, which are estimates, calculated probabilities involving distinct outcomes from a sample space are exact.