How do you find the slope and y intercept of \[y+1=1\left( x+2 \right)\]

Hint: The slope intercept form of a line is \[y=mx+b\], here m is the slope of the line and b is the Y-intercept of the line. To find the values of m and b for the given equation, we have to simplify it to express in slope intercept form. Then, comparing the coefficients of the equation we can find the slope and y intercept of the equation.

Complete step by step answer:
We are given the equation \[y+1=1\left( x+2 \right)\]. To simplify it we have to expand the bracket term, we can do it by multiplying the term outside the bracket with all the terms inside the bracket. However, as the term outside is 1 multiplying it with terms inside the bracket will make no difference. Simplifying this equation, it can be expressed as
\[\begin{align}
  & \Rightarrow y+1=x+2 \\
 & \Rightarrow y=x+1 \\
\end{align}\]
This equation is in the form of slope intercept form. Comparing it with the slope intercept form of the standard equation \[y=mx+b\], we get the values of both m and b as 1.

Thus, as m equals 1 the slope of the given equation is 1. Similarly, as b equals 1 the y intercept equals 1.

Note: we can also find the y intercept from the graph of the equation. The y intercept is the point where the graph cuts the y axis. As the given equation is linear its graph is a straight line.
We can draw its graph as follows:

From the above graph, we can say that the y intercept is 1.