Find the value of \[\sin ( - 210^\circ )\].
Answer
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Hint: Here we have to find the value of sine function at the angle of \[ - 210^\circ \]. To do this first we have to find the value of sine function for negative angles. Then we write this angle in terms of the angles whose value is known easily to us. Then we have to locate the quadrant on the Cartesian plane where the angle \[210^\circ \] is located. Then we solve it further till we find the value of \[\sin ( - 210^\circ )\].
Formula used: We have used the following formulas here to solve the given question,
\[sin(180 + \theta ) = - sin\theta \]
\[\sin (30^\circ ) = \dfrac{1}{2}\]
\[\sin ( - \theta ) = - \sin \theta \]
Complete step by step solution:
We are given here to find the value of \[\sin ( - 210^\circ )\]. Since we know that \[\sin ( - \theta ) = - \sin \theta \], we use this formula in our given question to move forward as,
\[\sin ( - 210^\circ ) = - \sin (210^\circ )\]
Since, we can write \[210^\circ \] as \[(180^\circ + 30^\circ )\], we replace \[210^\circ \] in the above step with \[(180^\circ + 30^\circ )\]\[ \Rightarrow \sin ( - 210^\circ ) = - \sin (180^\circ + 30^\circ )\]
Since given angle is third quadrant, sign of sine function will be negative and we also know that, \[sin(180 + \theta ) = - sin\theta \]
Using this, we get,
\[
\Rightarrow \sin ( - 210^\circ ) = - ( - \sin (30^\circ )) \\
\Rightarrow \sin ( - 210^\circ ) = \sin (30^\circ ) \\
\]
As, \[\sin (30^\circ ) = \dfrac{1}{2}\], we put this value in above step and move ahead as,
\[ \Rightarrow \sin ( - 210^\circ ) = \dfrac{1}{2}\]
Hence the value of the given function \[\sin ( - 210^\circ )\] comes out to be \[\dfrac{1}{2}\].
Note:
While finding the values of the various trigonometric functions for the angles which are not the common angles which we study normally like \[0^\circ ,30^\circ ,45^\circ ,60^\circ ,90^\circ ,180^\circ ,270^\circ ,360^\circ \], we try to break down or convert them in terms of these angles. We should be careful in locating the angle in quadrants as any mistake may lead to change in sign of the answer.
Formula used: We have used the following formulas here to solve the given question,
\[sin(180 + \theta ) = - sin\theta \]
\[\sin (30^\circ ) = \dfrac{1}{2}\]
\[\sin ( - \theta ) = - \sin \theta \]
Complete step by step solution:
We are given here to find the value of \[\sin ( - 210^\circ )\]. Since we know that \[\sin ( - \theta ) = - \sin \theta \], we use this formula in our given question to move forward as,
\[\sin ( - 210^\circ ) = - \sin (210^\circ )\]
Since, we can write \[210^\circ \] as \[(180^\circ + 30^\circ )\], we replace \[210^\circ \] in the above step with \[(180^\circ + 30^\circ )\]\[ \Rightarrow \sin ( - 210^\circ ) = - \sin (180^\circ + 30^\circ )\]
Since given angle is third quadrant, sign of sine function will be negative and we also know that, \[sin(180 + \theta ) = - sin\theta \]
Using this, we get,
\[
\Rightarrow \sin ( - 210^\circ ) = - ( - \sin (30^\circ )) \\
\Rightarrow \sin ( - 210^\circ ) = \sin (30^\circ ) \\
\]
As, \[\sin (30^\circ ) = \dfrac{1}{2}\], we put this value in above step and move ahead as,
\[ \Rightarrow \sin ( - 210^\circ ) = \dfrac{1}{2}\]
Hence the value of the given function \[\sin ( - 210^\circ )\] comes out to be \[\dfrac{1}{2}\].
Note:
While finding the values of the various trigonometric functions for the angles which are not the common angles which we study normally like \[0^\circ ,30^\circ ,45^\circ ,60^\circ ,90^\circ ,180^\circ ,270^\circ ,360^\circ \], we try to break down or convert them in terms of these angles. We should be careful in locating the angle in quadrants as any mistake may lead to change in sign of the answer.
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