How do you graph \[2x + y = 5\] by plotting points?
Answer
611.1k+ views
Hint: In this question, we need to plot a graph of the given linear equation. Note that the given equation is a linear equation. To plot the graph, we find the intercepts, so we set one variable to zero and obtain the other variable and vice versa. Firstly, to obtain the \[x\]-intercept, we set the value of y equal to zero and find the point. Then, to obtain the \[y\]-intercept, we set the value of x equal to zero and find the point. Then from obtained \[\left( {x,y} \right)\] points we plot a graph of the given equation in the x-y plane.
Complete step by step solution:
Write the given equation as shown below.
\[2x + y = 5\] …… (1)
We are asked to draw the graph of the above equation.
It is observed that the given equation is one of the equations of a straight line. We know this fact because both x and y terms in the equation are of power 1 (so they are not squared or square rooted terms).
We can simplify the given equation, so that our calculation becomes easier.
We draw the graph by finding \[x\]-intercept and \[y\]-intercept.
So we find the points of intercepts and then draw a line through them.
Finding the \[x\]-intercept:
The line crosses the x-axis at \[y = 0\].
Taking \[y = 0\] in the equation (1) we get,
\[ \Rightarrow 2x + 0 = 5\]
This can be written as,
\[ \Rightarrow 2x = 5\]
Dividing throughout by 3, we get,
\[ \Rightarrow \dfrac{{2x}}{2} = \dfrac{5}{2}\]
\[ \Rightarrow x = \dfrac{5}{2}\]
So the point is \[\left( {\dfrac{5}{2},0} \right)\].
Finding the \[y\]-intercept :
The line crosses the y-axis at \[x = 0\].
Taking \[x = 0\] in the equation (1) we get,
\[ \Rightarrow 2\left( 0 \right) + y = 5\]
This can be written as,
\[ \Rightarrow 0 + y = 5\]
\[ \Rightarrow y = 5\]
So the point is \[\left( {0,5} \right)\].
Hence the \[x\]-intercept is \[\left( {\dfrac{5}{2},0} \right)\] and the \[y\]-intercept is \[\left( {0,5} \right)\].
Now we plot the graph for the obtained points as shown below.
Note that the graph is a straight line.
Note:
We can also plot the graph of the linear equation by using slope and intercept form.
Students must remember that to obtain the \[x\]-intercept, we set the value of y equal to zero and find the point. Then, to obtain the \[y\]-intercept, we set the value of x equal to zero and find the point. Then from obtained \[(x,y)\]points we plot a graph of the given equation in the x-y plane.
Linear graphs have many applications. In our day-to-day life, we observe variation in the value of different quantities depending upon the variation in values of other quantities.
For example, if the number of persons visiting a cloth shop increases, then the earning of the shop also increases and vice versa.
Complete step by step solution:
Write the given equation as shown below.
\[2x + y = 5\] …… (1)
We are asked to draw the graph of the above equation.
It is observed that the given equation is one of the equations of a straight line. We know this fact because both x and y terms in the equation are of power 1 (so they are not squared or square rooted terms).
We can simplify the given equation, so that our calculation becomes easier.
We draw the graph by finding \[x\]-intercept and \[y\]-intercept.
So we find the points of intercepts and then draw a line through them.
Finding the \[x\]-intercept:
The line crosses the x-axis at \[y = 0\].
Taking \[y = 0\] in the equation (1) we get,
\[ \Rightarrow 2x + 0 = 5\]
This can be written as,
\[ \Rightarrow 2x = 5\]
Dividing throughout by 3, we get,
\[ \Rightarrow \dfrac{{2x}}{2} = \dfrac{5}{2}\]
\[ \Rightarrow x = \dfrac{5}{2}\]
So the point is \[\left( {\dfrac{5}{2},0} \right)\].
Finding the \[y\]-intercept :
The line crosses the y-axis at \[x = 0\].
Taking \[x = 0\] in the equation (1) we get,
\[ \Rightarrow 2\left( 0 \right) + y = 5\]
This can be written as,
\[ \Rightarrow 0 + y = 5\]
\[ \Rightarrow y = 5\]
So the point is \[\left( {0,5} \right)\].
Hence the \[x\]-intercept is \[\left( {\dfrac{5}{2},0} \right)\] and the \[y\]-intercept is \[\left( {0,5} \right)\].
Now we plot the graph for the obtained points as shown below.
Note that the graph is a straight line.
Note:
We can also plot the graph of the linear equation by using slope and intercept form.
Students must remember that to obtain the \[x\]-intercept, we set the value of y equal to zero and find the point. Then, to obtain the \[y\]-intercept, we set the value of x equal to zero and find the point. Then from obtained \[(x,y)\]points we plot a graph of the given equation in the x-y plane.
Linear graphs have many applications. In our day-to-day life, we observe variation in the value of different quantities depending upon the variation in values of other quantities.
For example, if the number of persons visiting a cloth shop increases, then the earning of the shop also increases and vice versa.
Recently Updated Pages
Write any three differences between metals and nonmetals class 10 social science CBSE

Amit standing on a horizontal plane finds a bird flying class 10 maths CBSE

Two circles of radii 5 cm and 3 cm intersect at two class 10 maths CBSE

Solve the following i John and Jivanti together have class 10 maths CBSE

What is the relation between orthocenter circumcentre class 10 maths CBSE

Two plane mirrors are inclined at 70circ A ray incident class 10 physics CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which country is known as "The land of Fire and Ice"?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

Choose the feminine form of the given noun Fox AFoxess class 10 english CBSE

