How do you graph the exponential function $ f\left( x \right) = {6^x} $ ?

Hint: A graph of a function f is the set of ordered pairs; the equation of graph is generally represented as $ y = f\left( x \right) $ , where x and $ f\left( x \right) $ are real numbers. We substitute the value of x and we determine the value of y and then we mark the points in the graph and we join the points.

Complete step by step solution:
Here, in the given question, we have to plot the graph for the given function. A graph of a function is set of ordered pairs and it is represented as $ y = f\left( x \right) $ , where x and $ f\left( x \right) $ are real numbers. These pairs are in the form of cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the graph equation $ y = f\left( x \right) = {6^x} $ .
Let us substitute the value of x as $ 1 $ .
 $ \Rightarrow y = {6^1} $
 $ \Rightarrow y = 6 $
Now, we consider the value of x as $ 0 $ , the value of y is
 $ \Rightarrow y = {6^0} $
 $ \Rightarrow y = 1 $
Now we consider the value of x as $ 2 $ , the value of y is
 $ \Rightarrow y = {6^2} $
 $ \Rightarrow y = 36 $
Now we draw a table for these values we have



We also know the nature of the graph of logarithmic function. Hence, we can now plot the graph of the given function $ y = f\left( x \right) = {6^x} $ . The graph plotted for these points is represented below:



Note: The graph is plotted x-axis versus y axis. The graph is two dimensional. By the equation of a graph, we can plot the graph by assuming the value of x. we can’t assume the value of y. because the value of y depends on the value of x. Hence, we have plotted the graph.