How do you graph y = $ \dfrac{1}{4}x-3 $ by plotting points?
Answer
624.9k+ views
Hint: Here in this question, we have to solve the equation given which is a linear equation in two variables. We will use the general form of the equation of slope and intercept to solve this problem. The general form of this equation is:
y = mx + c
where m is the slope and c is the constant.
After that, we will put the values for ‘x’ in order to find the value for ‘y’ for a corresponding value of ‘x’. Then plot all the values in a graph to obtain the line.
Complete step by step answer:
Now, let’s solve the question.
We already know that the slope-intercept form is a general form of a straight line and is expressed as y = mx + c where ‘m’ is a slope and c is a constant and intercepts are m and c.
So, for plotting a straight line, first, we have to convert the given equation into a slope-intercept form. Let’s study how!
First, write the equation from the question.
$ \Rightarrow $ y = $ \dfrac{1}{4}x-3......(i) $
As we can observe that the above equation is already in general form of straight line i.e. y = mx + c, here m = $ \dfrac{1}{4} $ and c = -3.
Now, we have to find the intercepts for x and y.
Let’s find y-intercept first. Substitute x = 0 in equation(i) we get:
$ \Rightarrow $ y = $ \dfrac{1}{4}(0)-3 $
Now we get the value of ‘y’ as:
$ \Rightarrow $ y = -3
$ \therefore $ y-intercept form is: $ \left( 0,-3 \right) $
Similarly, we will find x-intercept now. Put y = 0 in equation(i) we get:
$ \Rightarrow $ (0) = $ \dfrac{1}{4}x-3 $
Now, take 3 on the left side, the sign will get change:
$ \Rightarrow $ 3 = $ \dfrac{1}{4}x $
As $ \dfrac{1}{4} $ is in product with ‘x’, now it will be reciprocated and taken to the left side:
$ \Rightarrow 3\times \dfrac{4}{1}=x $
Now the value of x will be:
$ \Rightarrow $ x = 12
$ \therefore $ x-intercept will be: (12, 0)
Let’s plot the graph of the equation with the help of the intercepts.
The graph above is of y-intercept: (0, -3).
The graph above is of x-intercept: (12, 0).
Note:
We plotted the points by slope and intercept form so that it becomes easy to solve for a particular variable. It is the easiest approach to finding the coordinates. All you need to know the general form of the equation of a straight line. If you are not obtaining a straight line after plotting the points, it means you are going wrong somewhere in the calculation.
y = mx + c
where m is the slope and c is the constant.
After that, we will put the values for ‘x’ in order to find the value for ‘y’ for a corresponding value of ‘x’. Then plot all the values in a graph to obtain the line.
Complete step by step answer:
Now, let’s solve the question.
We already know that the slope-intercept form is a general form of a straight line and is expressed as y = mx + c where ‘m’ is a slope and c is a constant and intercepts are m and c.
So, for plotting a straight line, first, we have to convert the given equation into a slope-intercept form. Let’s study how!
First, write the equation from the question.
$ \Rightarrow $ y = $ \dfrac{1}{4}x-3......(i) $
As we can observe that the above equation is already in general form of straight line i.e. y = mx + c, here m = $ \dfrac{1}{4} $ and c = -3.
Now, we have to find the intercepts for x and y.
Let’s find y-intercept first. Substitute x = 0 in equation(i) we get:
$ \Rightarrow $ y = $ \dfrac{1}{4}(0)-3 $
Now we get the value of ‘y’ as:
$ \Rightarrow $ y = -3
$ \therefore $ y-intercept form is: $ \left( 0,-3 \right) $
Similarly, we will find x-intercept now. Put y = 0 in equation(i) we get:
$ \Rightarrow $ (0) = $ \dfrac{1}{4}x-3 $
Now, take 3 on the left side, the sign will get change:
$ \Rightarrow $ 3 = $ \dfrac{1}{4}x $
As $ \dfrac{1}{4} $ is in product with ‘x’, now it will be reciprocated and taken to the left side:
$ \Rightarrow 3\times \dfrac{4}{1}=x $
Now the value of x will be:
$ \Rightarrow $ x = 12
$ \therefore $ x-intercept will be: (12, 0)
Let’s plot the graph of the equation with the help of the intercepts.
The graph above is of y-intercept: (0, -3).
The graph above is of x-intercept: (12, 0).
Note:
We plotted the points by slope and intercept form so that it becomes easy to solve for a particular variable. It is the easiest approach to finding the coordinates. All you need to know the general form of the equation of a straight line. If you are not obtaining a straight line after plotting the points, it means you are going wrong somewhere in the calculation.
Recently Updated Pages
Write any three differences between metals and nonmetals class 10 social science CBSE

Amit standing on a horizontal plane finds a bird flying class 10 maths CBSE

Two circles of radii 5 cm and 3 cm intersect at two class 10 maths CBSE

Solve the following i John and Jivanti together have class 10 maths CBSE

What is the relation between orthocenter circumcentre class 10 maths CBSE

Two plane mirrors are inclined at 70circ A ray incident class 10 physics CBSE

Trending doubts
Which country is known as "The land of Fire and Ice"?

10 examples of evaporation in daily life with explanations

In which year voting age was reduced from 21 to 18?

Differentiate between Xylem and phloem class 10 biology CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

Draw a circuit diagram showing the cell switch and class 10 physics CBSE

