How do you factorize \[{y^2} + 27y\]?
Answer
602.7k+ views
Hint: In the given question, we have been given a polynomial. We have to factorize it. We are going to do it by taking the common term, reducing the power of all the terms by the power of the common term, taking it out of the bracket, following the procedure for the terms in the bracket and solving the question.
Formula used:
We are going to use the following formula:
\[{a^2} + na = a\left( {a + n} \right)\]
Complete step-by-step answer:
We have to factorize \[{y^2} + 27y\].
In the given expression, we have one common term, \[y\].
We are going to take it common.
So, we have, \[{y^2} + 27y = y\left( {y + 27} \right)\].
Note: In the given question, we had been given a polynomial. We had to factorize it. We did it by taking the common term, reducing the power of all the terms by the power of the common term, taking it out of the bracket, following the procedure for the terms in the bracket and solving the question. If there are more than one common term, we can take it out in the next step or in the same step itself, but care must be taken as exact correctness is necessary.
Formula used:
We are going to use the following formula:
\[{a^2} + na = a\left( {a + n} \right)\]
Complete step-by-step answer:
We have to factorize \[{y^2} + 27y\].
In the given expression, we have one common term, \[y\].
We are going to take it common.
So, we have, \[{y^2} + 27y = y\left( {y + 27} \right)\].
Note: In the given question, we had been given a polynomial. We had to factorize it. We did it by taking the common term, reducing the power of all the terms by the power of the common term, taking it out of the bracket, following the procedure for the terms in the bracket and solving the question. If there are more than one common term, we can take it out in the next step or in the same step itself, but care must be taken as exact correctness is necessary.
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