How do you graph $y=0x+3$ ?

Hint: The above question requires us to plot the graph of the linear equation $y=0x+3$ . We can do this by multiple methods, which include finding the points and then drawing the graph of the given line or we can write the equation in the slope-intercept form and find the points that lie on the same line.

Complete step by step solution:
Given the equation of the line is: $y=0x+3$
Let us compare the given equation to the general form of a line in the slope-intercept form, which is given by $y=mx+c$, where $m$ is the slope of the line and $c$ is the intercept of the line on the $y$ - axis.
After comparing the two equations we get the slope of the line as $m=0$ and the intercept as $c=3$
Now, let us find some points to plot the graph of the given line by substituting the values of $x$ and $y$
The equation is $y=0x+3$
Let us take $x=0$ then we get the value of $y=3$
Similarly, if we take $x=1$ then we get the value of $y=3$
For the value of $x=2$ also, we get the value of $y=3$
From the above values, we can conclude that for every value of $x$ we get the value of $y$ as $y=3$
Now, taking the points we have calculated, plot the graph for the given equation.
The graph of the equation is given below, where the blue line represents the line.


Note: From the graph, we can see that the given equation of a line represents a line that is parallel to the $x$- axis. Therefore, if ever equations like $y=c$ or $x=c$ are given, where $c$ means a constant, then on plotting the equation we will always get a parallel line to $x$- axis or $y$- axis respectively.