How do you plot the point $Q( - 9,0)?$

Hint: In this question we are given coordinates of X- axis and Y- axis . We have to plot them on the graph. So we will first draw the axis and then we will mark the coordinates step by step. We also have to tell where those coordinates lie on both the axes. As we know that there are four quadrants on the graph, we will also check in which quadrants in our coordinates lie.

Complete step by step answer:
Here we have the point: $Q( - 9,0)$ .
Let us first draw the X axis and Y axis. We will then mark the units along the x and y axis by taking $1$ unit for one box. Now let us plot the coordinates one by one.
Here the x coordinate of our coordinate is $ - 9$ and the y- coordinate of our coordinate is $0$ .
We can see that $ - 9$ is negative therefore, we will move $9$ places from origin along the x axis to the left.
Here the coordinate of y is $0$ , so we will not move up and hence the point will stay on the x axis only. So the coordinates will be marked as $9$ units and negative sides of the x- axis.
Let us plot the coordinates now:


Note:
We should note that here all coordinates lie on the x axis and y axis only. We have marked four quadrants on the graph paper too. We should know that in first quadrant, all the coordinates are positive i.e.
 $x > 0,y > 0$
In the second quadrant, x is negative and the value of y is positive: $x < 0,y > 0$
In the third quadrant, both the coordinates in x axis and y axis are negative. We can represent it as: $x < 0,y < 0$ .
In the fourth quadrant, the point on the x axis is positive and the point on the negative of y axis. We can represent it as:
$x > 0,y < 0$ .