How do you solve $-11+x-3=14-19+3$ ?

Hint: To solve $-11+x-3=14-19+3$ , we have to collect variables on LHS and constants on RHS. When a positive term is moved from one side to another, it will become negative. We also know that when we move a negative term from one side to another, it will become positive. By solving for x using algebraic rules, we will get the required solution.

Complete step by step solution:
We have to solve $-11+x-3=14-19+3$ . Let us collect variables on LHS and constants on RHS. We can rewrite the given equation as
$x=14-19+3+11+3$
Now, we have to solve the RHS. Let us first subtract 19 from 14.
$x=-5+3+11+3$
Let us add 3, 11 and 3.
$x=-5+17$
On further solving the RHS, we will get
$x=12$
Hence, the solution of $-11+x-3=14-19+3$ , is 12.

Note: Students must know algebraic rules to solve these types of problems. When a positive term is moved from one side to another, it will become negative. We also know that when we move a negative term from one side to another, it will become positive. Similarly, when a product term is moved from one side to another, it will become the divisor. The converse is also true. When we move a divisor from one side to another, it will become the multiplier. For example, let us consider $5x=25$ . When we move 5 to RHS, 25 gets divided by 5.
$\Rightarrow x=\dfrac{25}{5}=5$
Now, consider $\dfrac{x}{9}=3$ . When we move 9 from LHS to RHS, 3 gets multiplied by 9.
$\Rightarrow x=3\times 9=27$