If \[A = \left\{ {x,y,z} \right\}\] then the relation \[R = \left\{ {\left( {x,x} \right),\left( {y,y} \right),\left( {z,x} \right),\left( {z,y} \right)} \right\}\] is
(A) Symmetric
(B) Transitive
(C) None of these
(D) Both A and B
Answer
651.3k+ views
Hint:
In order to find the given relation is reflexive, symmetric, or transitive, we first need to understand the definition of the reflexivity, symmetry and transitivity holds for a set. The relation is reflexive if \[\left( {x,x} \right)\] belongs to the relation for all \[x\] belongs to the set. The relation is symmetric if \[\left( {x,y} \right)\] belongs to the relation implies that \[\left( {y,z} \right)\] belongs to the same relation. And the relation is transitive if \[\left( {x,y} \right)\& \left( {y,z} \right)\] belongs to the relation implies that \[\left( {x,z} \right)\] belongs to the same relation.
Complete step by step solution:
The relation R in A is said to be reflexive, if \[\left( {a,a} \right) \in R {\text{ for }} a \in A\].
The relation R in A is said to be symmetric, if \[\left( {a,b} \right) \in R \Rightarrow \left( {b,a} \right) \in R {\text{ for }} a, b \in A\].
The relation R is said to be transitive if \[\left( {x,y} \right) \in R {\text{ and }} \left( {y,z} \right) \in R \Rightarrow \left( {x,z} \right) \in R {\text{ for }}x, y, z \in A\].
As the given set A contains three elements, given as \[A = \left\{ {x,y,z} \right\}\] and the relation \[R\] does not contain \[\left( {z,z} \right)\] and \[z \in A\], so the relation \[R\] is not reflexive.
As \[\left( {z,x} \right)\] belongs to the given relation \[R\] and \[\left( {x,z} \right)\] does not belong to the given relation \[R\]. So by using the definition of symmetry.
So, it can be concluded that the given relation is not symmetric.
As \[\left( {z,x} \right) \& \left( {x,x} \right)\] both belong to the given relation \[R\] and \[\left( {z,x} \right)\] also belong to the given relation\[R\] and \[\left( {z,y} \right) \& \left( {y,y} \right)\] both belong to the given relation \[R\] and \[\left( {z,y} \right)\]also belong to the relation \[R\].
From the above argument it can be concluded that, if \[\left( {x,y} \right)\& \left( {y,z} \right)\] are belong to \[R\] implies that \[\left( {x,z} \right)\] belongs to the relation \[R\], then the relation is transitive.
Therefore, the given relation is transitive.
Hence, the correct option is B.
Note:
A relation is a relationship between sets of values or it is a subset of the Cartesian product. A function is a relation in which there is only one output for each input and a relation is denoted by \[R\] and a function is denoted by \[F\].
In order to find the given relation is reflexive, symmetric, or transitive, we first need to understand the definition of the reflexivity, symmetry and transitivity holds for a set. The relation is reflexive if \[\left( {x,x} \right)\] belongs to the relation for all \[x\] belongs to the set. The relation is symmetric if \[\left( {x,y} \right)\] belongs to the relation implies that \[\left( {y,z} \right)\] belongs to the same relation. And the relation is transitive if \[\left( {x,y} \right)\& \left( {y,z} \right)\] belongs to the relation implies that \[\left( {x,z} \right)\] belongs to the same relation.
Complete step by step solution:
The relation R in A is said to be reflexive, if \[\left( {a,a} \right) \in R {\text{ for }} a \in A\].
The relation R in A is said to be symmetric, if \[\left( {a,b} \right) \in R \Rightarrow \left( {b,a} \right) \in R {\text{ for }} a, b \in A\].
The relation R is said to be transitive if \[\left( {x,y} \right) \in R {\text{ and }} \left( {y,z} \right) \in R \Rightarrow \left( {x,z} \right) \in R {\text{ for }}x, y, z \in A\].
As the given set A contains three elements, given as \[A = \left\{ {x,y,z} \right\}\] and the relation \[R\] does not contain \[\left( {z,z} \right)\] and \[z \in A\], so the relation \[R\] is not reflexive.
As \[\left( {z,x} \right)\] belongs to the given relation \[R\] and \[\left( {x,z} \right)\] does not belong to the given relation \[R\]. So by using the definition of symmetry.
So, it can be concluded that the given relation is not symmetric.
As \[\left( {z,x} \right) \& \left( {x,x} \right)\] both belong to the given relation \[R\] and \[\left( {z,x} \right)\] also belong to the given relation\[R\] and \[\left( {z,y} \right) \& \left( {y,y} \right)\] both belong to the given relation \[R\] and \[\left( {z,y} \right)\]also belong to the relation \[R\].
From the above argument it can be concluded that, if \[\left( {x,y} \right)\& \left( {y,z} \right)\] are belong to \[R\] implies that \[\left( {x,z} \right)\] belongs to the relation \[R\], then the relation is transitive.
Therefore, the given relation is transitive.
Hence, the correct option is B.
Note:
A relation is a relationship between sets of values or it is a subset of the Cartesian product. A function is a relation in which there is only one output for each input and a relation is denoted by \[R\] and a function is denoted by \[F\].
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

