If a member, whose tensile strength is more than \[1.5\] times the shear strength and is subjected to an axial load up to failure, the failure of the member will occur by
A. Maximum normal stress
B. Maximum shear stress
C. Normal stress or shear stress
D. None of the above

Hint: First of all, we need to analyze the tensile strength and shear strength for a member which is loaded to an axial, from that information we will obtain the required answer. It is a force that appears to cause a material’s deformation by slippage along a plane or planes parallel to the stress applied.

Complete answer:
We know that in a member that is subjected to an axial load, the maximum shear stress induced equals half of the maximum normal stress. Therefore, the failure occurs due to shearing for a product with tensile strength greater than \[1.5\] times the shear strength.
Hence, the required answer is maximum shear stress.

So, the correct answer is “Option B”.

Additional Information:
- Tensile strength: Tensile strength is a calculation of the force needed to pull something to the point that it falls, such as rope, wire, or a structural beam.
- Shear strength: Shear strength is a material or component's strength against the form of yield or structural failure when shear fails with the material or component.

Note:
- A metal’s tensile strength is basically its ability to resist tensile loads without failure. Since brittle metals are more likely to rupture, this is an essential factor in the metal forming process.
- A material's tensile strength is the maximum amount of tensile stress that it can take, such as cracking, before failure.
- A shear load is a force tending to cause a sliding failure along a plane parallel to the direction of the force on a material.