If $\mathrm\alpha\;\mathrm{and}\;\mathrm\beta$ are the zeroes of the quadratic polynomial $f(x) = ax^2+ bx + c$, then evaluate the following-
$\dfrac1{\mathrm\alpha}+\dfrac1{\mathrm\beta}-2\mathrm{\mathrm\alpha\mathrm\beta}$
Answer
663.6k+ views
Hint: This is a question of quadratic equations. We will first simplify the term $\dfrac{1}{\alpha } + \dfrac{1}{\beta }$ in the form of the sum ($\alpha + \beta $) and the product of the roots $\alpha \beta $. Once we do that, we can substitute the values of the sum and the product of the roots of the quadratic equation $f(x) = ax^2+ bx + c$ respectively using the formulas-
$\mathrm\alpha+\mathrm\beta=-\dfrac{\mathrm b}{\mathrm a}\\\mathrm{\mathrm\alpha\mathrm\beta}=\dfrac{\mathrm c}{\mathrm a}$
Complete step-by-step answer:
We have to convert the given expression such that it can be expressed in the form of $\mathrm\alpha+\mathrm\beta\;\mathrm{and}\;\mathrm{\mathrm\alpha\mathrm\beta}$ only, so that we can apply the given formulas, substitute the values and find the result.
So we will convert the equation by taking the LCM as follows-
$\dfrac1{\mathrm\alpha}+\dfrac1{\mathrm\beta}-2\mathrm{\mathrm\alpha\mathrm\beta}\\=\dfrac{\mathrm\beta+\mathrm\alpha}{\mathrm{\mathrm\alpha\mathrm\beta}}-2\mathrm{\mathrm\alpha\mathrm\beta}$
We have now converted the expression in terms of the sum and the product of the roots of the quadratic equation. Now, we will simplify this by applying the formula for the relationship between the roots and the coefficients of the equation. So, we will substitute the given formula in this expression to find its value using-
$\mathrm\alpha+\mathrm\beta=-\dfrac{\mathrm b}{\mathrm a}\\\mathrm{\mathrm\alpha\mathrm\beta}=\dfrac{\mathrm c}{\mathrm a}$
$=\dfrac{-\left({\displaystyle\dfrac{\mathrm b}{\mathrm a}}\right)}{\displaystyle\dfrac{\mathrm c}{\mathrm a}}-2\dfrac{\mathrm c}{\mathrm a}\\=-\dfrac{\mathrm b}{\mathrm c}-\dfrac{2\mathrm c}{\mathrm a}\\=\dfrac{-\left(\mathrm{ab}+2\mathrm c^2\right)}{\mathrm{ac}}$
This is the required answer.
Note:The above given formula signifies that the sum of roots of a quadratic equation is the negative of the ratio of coefficient of $x$ and $x^2$. Also, the product of roots is the ratio of constant term and coefficient of $x^2$. It is also recommended to simplify the final answer.
$\mathrm\alpha+\mathrm\beta=-\dfrac{\mathrm b}{\mathrm a}\\\mathrm{\mathrm\alpha\mathrm\beta}=\dfrac{\mathrm c}{\mathrm a}$
Complete step-by-step answer:
We have to convert the given expression such that it can be expressed in the form of $\mathrm\alpha+\mathrm\beta\;\mathrm{and}\;\mathrm{\mathrm\alpha\mathrm\beta}$ only, so that we can apply the given formulas, substitute the values and find the result.
So we will convert the equation by taking the LCM as follows-
$\dfrac1{\mathrm\alpha}+\dfrac1{\mathrm\beta}-2\mathrm{\mathrm\alpha\mathrm\beta}\\=\dfrac{\mathrm\beta+\mathrm\alpha}{\mathrm{\mathrm\alpha\mathrm\beta}}-2\mathrm{\mathrm\alpha\mathrm\beta}$
We have now converted the expression in terms of the sum and the product of the roots of the quadratic equation. Now, we will simplify this by applying the formula for the relationship between the roots and the coefficients of the equation. So, we will substitute the given formula in this expression to find its value using-
$\mathrm\alpha+\mathrm\beta=-\dfrac{\mathrm b}{\mathrm a}\\\mathrm{\mathrm\alpha\mathrm\beta}=\dfrac{\mathrm c}{\mathrm a}$
$=\dfrac{-\left({\displaystyle\dfrac{\mathrm b}{\mathrm a}}\right)}{\displaystyle\dfrac{\mathrm c}{\mathrm a}}-2\dfrac{\mathrm c}{\mathrm a}\\=-\dfrac{\mathrm b}{\mathrm c}-\dfrac{2\mathrm c}{\mathrm a}\\=\dfrac{-\left(\mathrm{ab}+2\mathrm c^2\right)}{\mathrm{ac}}$
This is the required answer.
Note:The above given formula signifies that the sum of roots of a quadratic equation is the negative of the ratio of coefficient of $x$ and $x^2$. Also, the product of roots is the ratio of constant term and coefficient of $x^2$. It is also recommended to simplify the final answer.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

