If the upper and the lower limits of a class interval are 16 and 10, the class-interval is :
A. 10-16
B. 16-10
C. 10-16 or 16-10
D. None of these

Hint: Here the limits of a class interval are nothing but the range of the class interval, i.e, the lower limit of a class is the smallest data value in the class interval whereas the upper class limit of a class is the largest data value that can go into the class in a class interval. Class limits have the same accuracy as the data values, as the same number of decimal places as the data values.

Complete step-by-step solution:
We know that the lower limit of every class in that particular class interval is the smallest value in the class.
On the other hand, the upper limit for every class is the greatest value in that class of a class interval.
Here given that the upper and the lower limits of a class interval are 16 and 10 respectively.
Now finding out which is the lower limit and which one is the upper limit.
The lower limit is 10 as given.
The upper limit is 16 as given.
$\therefore $The lower limit of the class interval is 10.
$\therefore $The upper limit of the class interval is 16.
As discussed in any class interval the lower limit should be shown first in a class interval and the upper limit should be shown at the end of a class interval.
Here the class interval should be written as lower limit – upper limit.
$\therefore $The class interval is written as : $10 - 16$
The class interval is $10 - 16$

Option A is the correct answer.

Note: While writing any class interval of any class in the statistics, it should be written in such a way that the lower limit should be written first and then the upper limit is written.