If we have a trigonometric equation as \[2\sin \theta + \tan \theta = 0\], then the general values of \[\theta \] are
1. \[2n\pi \pm \dfrac{\pi }{3}\]
2. \[n\pi ,2n\pi \pm \dfrac{{2\pi }}{3}\]
3. \[n\pi ,2n\pi \pm \dfrac{\pi }{3}\]
4. \[n\pi ,n\pi + \dfrac{{2\pi }}{3}\]
Answer
567.3k+ views
Hint: The given question deals with finding the general values of \[\theta \] from the given expression. We will convert all the terms into their respective sine and cosine expressions so as to ease the calculations. We will Simplify the given equation as much as possible by using various arithmetic operators and trigonometric functions. Take into consideration all the possible values of \[\theta \] and find the respective general values.
Complete step-by-step solution:
Sine function of an angle is the ratio between the opposite side length to that of the hypotenuse.
Cosine function of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse.
The tangent function is the ratio of the length of the opposite side to that of the adjacent side. It should be noted that the tan can also be represented in terms of sine and cos as their ratio.
We are given \[2\sin \theta + \tan \theta = 0\]
This equation can be rewritten as \[2\sin \theta + \dfrac{{\sin \theta }}{{\cos \theta }} = 0\]
Which simplifies to
\[2\sin \theta \cos \theta + \sin \theta = 0\]
On further simplification of the expression we get ,
\[ \sin \theta \left( {2\cos \theta + 1} \right) = 0 \]
Therefore we have the following
\[\sin \theta = 0\] or \[\left( {2\cos \theta + 1} \right) = 0\]
\[\sin \theta = 0\] or \[\cos \theta = - \dfrac{1}{2}\]
Therefore we get ,
\[\sin \theta = 0\] gives us \[\theta = n\pi \]
And \[\cos \theta = \cos \left( {\dfrac{{2\pi }}{3}} \right)\]
Hence we get the general values as \[\theta = n\pi ,2n\pi \pm \dfrac{{2\pi }}{3}\]
Therefore option (2) is the correct answer.
Note: We must have a strong grip over the concepts of trigonometry , its related formulas and rules in order to solve such types of questions. In addition to this we must know the basic trigonometric identities to simplify the expressions at each step. Do the calculations very carefully as they may alter the solution.
Complete step-by-step solution:
Sine function of an angle is the ratio between the opposite side length to that of the hypotenuse.
Cosine function of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse.
The tangent function is the ratio of the length of the opposite side to that of the adjacent side. It should be noted that the tan can also be represented in terms of sine and cos as their ratio.
We are given \[2\sin \theta + \tan \theta = 0\]
This equation can be rewritten as \[2\sin \theta + \dfrac{{\sin \theta }}{{\cos \theta }} = 0\]
Which simplifies to
\[2\sin \theta \cos \theta + \sin \theta = 0\]
On further simplification of the expression we get ,
\[ \sin \theta \left( {2\cos \theta + 1} \right) = 0 \]
Therefore we have the following
\[\sin \theta = 0\] or \[\left( {2\cos \theta + 1} \right) = 0\]
\[\sin \theta = 0\] or \[\cos \theta = - \dfrac{1}{2}\]
Therefore we get ,
\[\sin \theta = 0\] gives us \[\theta = n\pi \]
And \[\cos \theta = \cos \left( {\dfrac{{2\pi }}{3}} \right)\]
Hence we get the general values as \[\theta = n\pi ,2n\pi \pm \dfrac{{2\pi }}{3}\]
Therefore option (2) is the correct answer.
Note: We must have a strong grip over the concepts of trigonometry , its related formulas and rules in order to solve such types of questions. In addition to this we must know the basic trigonometric identities to simplify the expressions at each step. Do the calculations very carefully as they may alter the solution.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

