If x grams of metal sulphate on heating gives y g metal oxide then which of the following relations is correct? (E = equivalent weight of metal)
(A) $\dfrac{x}{E+30}=\dfrac{y}{E+16}$
(B) $\dfrac{x}{E+48}=\dfrac{y}{E+16}$
(C) $\dfrac{x}{E+48}=\dfrac{y}{E+8}$
(D) $\dfrac{x}{E+8}=\dfrac{y}{E+48}$

Hint: Equivalent weight is defined as the weight of an element or compound which combines with or displaces 8 grams of oxygen or 1.00797 grams of hydrogen.

Complete step by step solution:
Given in the question,
It is given that the mass of metal sulphate = x grams
Mass of the metal oxide = y grams
The gram equivalent weight of the metal oxide will be equal to the gram equivalent weight of the metal sulphide
Equivalent weight of ${{M}_{x}}S{{O}_{4}}$= equivalent weight of ${{M}_{y}}N{{O}_{3}}$
We know that the equivalent weight of oxygen is always fix i.e. a metal oxide = $\dfrac{y}{E+8}$

Hence the correct answer is option (C).

Additional information:
In some of the cases the equivalent weight is determined by the number of replaceable H atoms. The replaceable hydrogen atoms means that the number of hydrogen atoms lessened in that compound after the reaction. It is mathematically expressed as the ratio of molecular mass of the number of replaceable hydrogen ions. Molecular weight is the proportion of the aggregate of the nuclear weight estimations of the particle in an atom. The sub atomic weight is utilized to decide the stoichiometry in the compound responses and the conditions.


Note: Don’t get confuse between the equivalent weight and the molecular weight of an element or compound because the molecular weight of an element or the compound because molecular weight of the element or the compound which is also known as the molecular mass is defined as the mass of the substance based on the 12 as the atomic weight of chlorine 35.5.