In a school X, 48 students appeared for the ${{10}^{th}}$ class exam out of which 36 students passed. In another school Y, 30 students appeared, and 24 students passed. If the District Educational Officer wants to give an award on the basis of pass percentage. To which school will he give the award?

Hint: Calculate the passing percentage of both the classes that is X and Y using the formula $=\dfrac{\text{passed students}}{\text{total students}}\times 100$ , the class with the higher percentage will be awarded.

Complete step-by-step answer:
Here, we are given that in school X, total 48 students are there out of which 36 students passed.
So, we will find students passed percentage using the formula $=\dfrac{\text{passed students}}{\text{total students}}\times 100$
We have $\text{passed students}=\text{36}$ , $\text{total students}=48$ . Substituting the value in the formula, we get
$=\dfrac{\text{passed students}}{\text{total students}}\times 100$
$=\dfrac{36}{48}\times 100$
On dividing by 12 in denominator and numerator, we get
$=\dfrac{3}{4}\times 100=75\%$
Thus, in school X, 75% of students are passed.
Similarly, taking school Y where a total 30 students are there out of which 24 students passed.
We have $\text{passed students}=24$ , $\text{total students}=30$ . Substituting the value in the formula, we get
$=\dfrac{\text{passed students}}{\text{total students}}\times 100$
$=\dfrac{24}{30}\times 100$
On dividing by 6 in denominator and numerator, we get
$=\dfrac{4}{5}\times 100=80\%$
Thus, in school Y, 80% of students are passed.
As we can see that in school Y percentage of students passed is more than school X.
So, the District Educational officer will give the award to school Y.

Note: Another approach to solve this problem is by finding the number of students failed and its percentage. Then subtracting that value from 100%. For example: it is given that in school X, total 48 students are there out of which 36 students passed. So, number of fail students will be:
$\text{failed students=total students}-\text{passed students}$
$=48-36=12$
Now for finding failed percentage using the formula $=\dfrac{\text{failed students}}{\text{total students}}\times 100=\dfrac{12}{48}\times 100=25\%$
Now, to find pass percentage we will subtract failed percentage from 100%, we will get
$=100\%-25\%=75\%$ . So, the answer will remain the same.