In a T.T match between Geeta and Ritu, the probability of the winning of Ritu is $0.73$. Find the probability of winning Geeta.

Hint: We know that the total probability is always $1$ so we can write it as the form of addition, $P$(Winning of Geeta ), and $P$ (Winning of Ritu) is equal to $1$.
When we subtract $P$ (Winning of Ritu) from $1$ to get the required answer.

Complete step by step answer:
It is given that the winning of Geeta is a complementary event to winning of Ritu
That is $P$ (winning of Ritu )$ = 0.73$
Here we need to find the probability of winning Geeta.
Thus, we know the concept of the total probability
Therefore, we can say that
$P$ (Winning of Ritu)$ + $P(Winning of Geeta)$ = 1$
Now we have to find the probability of winning Geeta.
So we can write it as,
$\Rightarrow P$ (winning of Geeta) =$1 - $P (Winning of Ritu)
By substituting the value of the probability of the winning of Ritu and we get,
$\Rightarrow P$ (winning of Geeta)$ = $$1 - 0.73$
On subtracting the probability of winning Ritu from $1$
$\Rightarrow $ Probability of Winning Geeta $ = 0.27$

Therefore, the probability of winning of Geeta is $0.27$.

Note:
We can also face problems in place of “not E” $\left( {{\text{not E}}} \right)$ is given.
For instance, you have to find the probability of $P\left( {{\text{not E}}} \right)$so the manner of the calculating the probability of $P\left( {{\text{not E}}} \right)$ is the same as the probability of $P\left( {{\text{not E}}} \right)$directly write the following expression:$P\left( {{\text{not E}}} \right) = 1 - P(E)$
Memorizing this concept will save you a lot of time in solving questions in the competitive exam or in the test.