In case of a virtual and erect image, the magnification created by the mirror is
A.) Positive
B.) Negative
C.) Unity
D.) Infinity

Hint: The magnification, m, is defined as the ratio of the height of the image to the height of the object and is closely related to the distance of the image to the ground. A 1 (plus or minus) magnification implies that the image is the same dimension as the object itself.

Complete step-by-step answer:

In both concave and convex mirrors, the magnification of a mirror in case of a simulated and erect image is positive. The picture is broadened or magnified.

Hence, option A is correct.

Additional Information:
Virtual image is a set of focal points created by diverging-ray extensions. In other words, a virtual image is identified by tracing actual rays that appear backwards from an optical system (lens, mirror, or any combination) to assumed or visible ray divergence sources. Virtual rays are conventionally represented by dotted lines in optical machine diagrams.

NOTE: For optics, an erect image is one that looks right upside down. If both rays converge at a given point, an erect image is formed. It is an image in which the directions are the same as those in the frame, in contrast to an inverted image. This is one of the image properties developed in a mirror plane. Many telescopes and other instruments such as the camera obscura project an inverted image on the surface of vision. Various means such as mirrors and compound prism elements are used in order to create an erect portrait. A typical example of an erect image is a person's face in a default plane mirror.