In the given figure a semicircle is drawn with the centre O as centre and AB as diameter. Semicircles are drawn with AO and BO as diameter. If AB $=$ 28 cm, find the perimeter of the shaded region.
A.98 cm
B.48 cm
C.80 cm
D.88 cm
Answer
594.5k+ views
Hint: Perimeter of circle i.e. circumference of a circle is given as $2\pi r$, where r is the radius of the circle, and value of $\pi $ is $\dfrac{22}{7}$. Perimeter is defined as the sum of the path of that curve. Diameter is given as twice the radius of any circle. Use these concepts to solve the given problem.
Complete step by step answer:
So, we need to find the perimeter of the shaded region. And as we know the perimeter of any curve is the length of the path of that curve. It means we need to add the path length of the shaded region i.e. length of the Arc ATB $+$ length of Arc $A{{T}_{1}}O$ $+$ length of Arc $O{{T}_{2}}B$.
As we know the diameter of the larger semicircle is 28 cm and hence the diameter of smaller semicircle will be $\dfrac{28}{2}=14cm$
Now, we know the circumference/ perimeter of any full circle is $2\pi r$ , where r is the radius of that circle.
It means the perimeter of the curve part of the semi-circle (leaving diameter) is given as $\dfrac{2\pi r}{2}=\pi r$ .
Now, as we have perimeter of shaded region as
Perimeter of shaded region $=$ Arc ATB $+$ Arc $A{{T}_{1}}O$ \[+\] Arc \[O{{T}_{2}}B\]
Hence, radius of larger semicircle \[=\dfrac{diameter}{2}\]
\[=\dfrac{28}{2}=14cm\]
And radius of smaller semi-circle \[=\dfrac{diameter}{2}\]
\[=\dfrac{14}{2}=7cm\]
Hence, we can write the perimeter of shaded region as
\[=\pi \times \] radius of larger semi-circle \[+2\pi \times \] radius of smaller semi-circle
\[=\pi \times 14+2\pi \times 7\]
\[=14\pi +14\pi \]
\[=28\pi \]
So, perimeter of shaded region \[=28\pi \]
We know the value of \[\pi \] is \[\dfrac{22}{7}\]
So, we get perimeter of shaded region \[=28\times \dfrac{22}{7}\]
\[=4\times 22\]
\[=88cm\]
Hence, option (D) is the correct answer.
Note: Don’t consider the diameter of the larger semi-circle in the calculation of the perimeter of it or with the shaded region as well. So, be clear with the definition of perimeter and involve only the path of the shaded region. Don’t use any other length to get the perimeter.Be clear with the formula of circumference and area of circle. Area is given as $\pi {{r}^{2}}$ and circumference is given as $2\pi r$. Don’t use the formulae in a reverse manner, it is the general confusion among the students.
Complete step by step answer:
So, we need to find the perimeter of the shaded region. And as we know the perimeter of any curve is the length of the path of that curve. It means we need to add the path length of the shaded region i.e. length of the Arc ATB $+$ length of Arc $A{{T}_{1}}O$ $+$ length of Arc $O{{T}_{2}}B$.
As we know the diameter of the larger semicircle is 28 cm and hence the diameter of smaller semicircle will be $\dfrac{28}{2}=14cm$
Now, we know the circumference/ perimeter of any full circle is $2\pi r$ , where r is the radius of that circle.
It means the perimeter of the curve part of the semi-circle (leaving diameter) is given as $\dfrac{2\pi r}{2}=\pi r$ .
Now, as we have perimeter of shaded region as
Perimeter of shaded region $=$ Arc ATB $+$ Arc $A{{T}_{1}}O$ \[+\] Arc \[O{{T}_{2}}B\]
Hence, radius of larger semicircle \[=\dfrac{diameter}{2}\]
\[=\dfrac{28}{2}=14cm\]
And radius of smaller semi-circle \[=\dfrac{diameter}{2}\]
\[=\dfrac{14}{2}=7cm\]
Hence, we can write the perimeter of shaded region as
\[=\pi \times \] radius of larger semi-circle \[+2\pi \times \] radius of smaller semi-circle
\[=\pi \times 14+2\pi \times 7\]
\[=14\pi +14\pi \]
\[=28\pi \]
So, perimeter of shaded region \[=28\pi \]
We know the value of \[\pi \] is \[\dfrac{22}{7}\]
So, we get perimeter of shaded region \[=28\times \dfrac{22}{7}\]
\[=4\times 22\]
\[=88cm\]
Hence, option (D) is the correct answer.
Note: Don’t consider the diameter of the larger semi-circle in the calculation of the perimeter of it or with the shaded region as well. So, be clear with the definition of perimeter and involve only the path of the shaded region. Don’t use any other length to get the perimeter.Be clear with the formula of circumference and area of circle. Area is given as $\pi {{r}^{2}}$ and circumference is given as $2\pi r$. Don’t use the formulae in a reverse manner, it is the general confusion among the students.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

