Is diffraction related to wavelength?

Hint: Diffraction is a term that describes a variety of events that occur when a wave collides with a barrier or an opening. It's described as the bending of waves around the corners of an obstruction or through an aperture into the region of the barrier's geometrical shadow. The diffracting item or aperture effectively becomes the propagating wave's secondary source.

Complete answer:
The wavelength of a periodic wave is its spatial period, or the distance over which the wave's form repeats. It's the distance between two adjacent corresponding points of the same phase on the wave, such two adjacent crests, troughs, or zero crossings, and it's a feature of both travelling and standing waves, as well as other spatial wave patterns. The spatial frequency is the inverse of the wavelength. The Greek letter lambda is often used to represent wavelength. Modulated waves, as well as the sinusoidal envelopes of modulated waves or waves generated by the interference of multiple sinusoids, are sometimes referred to as wavelengths.
When light bends when it passes across a border between two distinct media, each having a different index of refraction, it is called refraction. Diffraction, on the other hand, happens when light bends in the same medium. Light waves “squeeze” through narrow holes or "curve" around sharp edges, causing the bending. Diffraction only happens via small holes or across small grooves because light waves are so small (on the order of 400 to 700 nanometers). Furthermore, waves diffract optimally when the diffraction aperture (or getting our groove) has the same size as the wavelength. As a result, light diffracts more in tiny holes than in larger ones.
The angle of diffraction (theta) and wavelength have a direct relationship in the formula for diffraction: $ d\text{ }\left( sin\text{ }\theta \right)\text{ }=\text{ }m\text{ }\left( \lambda \right) $ for constructive interference.
(There is a formula for destructive interference that is similar.)
However, because both variables are on opposing sides of the equal sign, it's apparent that as the wavelength rises, the angle of diffraction increases. The angle of diffraction, on the other hand, diminishes as the wavelength decreases.
In other words, the angle of diffraction is proportional to the wavelength size.
As a result, red light (which has a longer wavelength) diffracts more than blue light (short wavelength).

Note:
The Huygens–Fresnel principle, which treats each point in a propagating wavefront as a collection of discrete spherical wavelets, describes the diffraction phenomena in classical physics. When a coherent source (such as a laser) hits a slit/aperture that is similar in size to its wavelength, as illustrated in the included image, the distinctive bending pattern is most prominent. This is owing to the addition, or interference, of various locations on the wavefront (or, equivalently, each wavelet) that travel to the registering surface along routes of varying lengths.