${K_2}S{O_4}$ does not undergo hydrolysis. If true, write $1$, else write $0$.

Hint: We know that ${K_2}S{O_4}$ is a salt of a strong acid and a strong base. The strong base is $KOH$ and the strong acid is ${H_2}S{O_4}$. The $pH$ of a salt made from strong acid and strong base is always $7$.

Complete step by step answer:
We know that ${K_2}S{O_4}$ is a salt of strong acid and strong base. And always remember that salt of strong acid and strong base does not undergo hydrolysis. In a salt of strong base and strong acid neither the cation undergoes hydrolysis nor the anion undergo hydrolysis. There is no change of concentration of the hydrogen ion and hydroxide ion. This is the reason why the solution is neutral. The $pH$ of the solution of ${K_2}S{O_4}$ will be $7$. So, from the above explanation it is clear to us that ${K_2}S{O_4}$ will not undergo hydrolysis.

The statement in the given question is true so the correct answer is: $1$

Additional information: The $pH$ of the solution of a salt of strong base and weak acid is always greater than $7$ and less than$14$. The $pH$of the solution of a salt of a strong acid and weak base is always less than $7$. Some of the examples of salts of strong acid and strong base are $KCl,NaCl$.

Note:
Always remember that ${K_2}S{O_4}$ is a salt of strong base and strong acid. It cannot undergo hydrolysis. The $pH$ of the solution of ${K_2}S{O_4}$ will always be $7$.${K_2}S{O_4}$ is also known as potassium sulphate. It is a water-soluble salt. It is used in fertilisers because it provides both sulphur and potassium. It helps in high quality cultivation