When an object undergoes acceleration:
a) Its speed always increases
b) its velocity always increases
c)It always falls down towards the earth
d) a net force always acts on it
Answer
651.3k+ views
Hint: All the above options satisfy the conditions when an object is accelerating. Define the acceleration to the general form. Further, we have to manipulate the other options on the basis that in any given circumstances the condition is not violated.
Complete step-by-step answer:
Let us first dine acceleration of a body.
Acceleration is defined as how fast a body changes its velocity with respect to time. Mathematically we can write it as $\overline{a}=\dfrac{\Delta v}{\Delta t}= \displaystyle \lim_{\Delta t \to 0} \dfrac{dv}{dt}$
Now let us manipulate each and every case one by one,
a) Its speed always increases with time
b) Its velocity always increases with time
If we consider a body in circular motion we say that it experiences a centripetal force given by
$\overline{F}=\dfrac{m{{v}^{2}}}{r}$ where m is the mass of the object, v is the speed of the object and r is the radius of the circular path. The object is said to be under centripetal acceleration. Here acceleration is given by $\dfrac{{{v}^{2}}}{r}$ . But in this case v i.e. speed does not change with time. Speaking about the velocity, the magnitude remains the same but its direction keeps on changing in the circular path. Hence it’s not necessary that speed as well as velocity increases if the body is under acceleration .
b)An object falling towards the earth
when an object falls towards the earth there is no doubt it would accelerate due to gravitational force. But it is always not necessary that an object falling towards the earth only accelerated. Like the case a the particle is moving in a circle and is under acceleration
d) A net force always acts on it
From Newton’s second law we state that force on an object is given by i.e.
${{\overline{F}}_{NET}}=m\overline{a}$ where m is the mass of the object and a is its acceleration
Let us say if you are applying a force on a wall or when we stand we apply force on the ground, but neither the wall nor the ground does not move. It is because the net force is zero. Hence, if there is a net force acting on a body it will be under acceleration.
Hence the correct option to the above answer is d.
Note: The rate at which the velocity of an object changes is the acceleration of the object. It is to be noted that the velocity decreases when there is deceleration. Deceleration is equal to acceleration but they differ by minus sign.
Complete step-by-step answer:
Let us first dine acceleration of a body.
Acceleration is defined as how fast a body changes its velocity with respect to time. Mathematically we can write it as $\overline{a}=\dfrac{\Delta v}{\Delta t}= \displaystyle \lim_{\Delta t \to 0} \dfrac{dv}{dt}$
Now let us manipulate each and every case one by one,
a) Its speed always increases with time
b) Its velocity always increases with time
If we consider a body in circular motion we say that it experiences a centripetal force given by
$\overline{F}=\dfrac{m{{v}^{2}}}{r}$ where m is the mass of the object, v is the speed of the object and r is the radius of the circular path. The object is said to be under centripetal acceleration. Here acceleration is given by $\dfrac{{{v}^{2}}}{r}$ . But in this case v i.e. speed does not change with time. Speaking about the velocity, the magnitude remains the same but its direction keeps on changing in the circular path. Hence it’s not necessary that speed as well as velocity increases if the body is under acceleration .
b)An object falling towards the earth
when an object falls towards the earth there is no doubt it would accelerate due to gravitational force. But it is always not necessary that an object falling towards the earth only accelerated. Like the case a the particle is moving in a circle and is under acceleration
d) A net force always acts on it
From Newton’s second law we state that force on an object is given by i.e.
${{\overline{F}}_{NET}}=m\overline{a}$ where m is the mass of the object and a is its acceleration
Let us say if you are applying a force on a wall or when we stand we apply force on the ground, but neither the wall nor the ground does not move. It is because the net force is zero. Hence, if there is a net force acting on a body it will be under acceleration.
Hence the correct option to the above answer is d.
Note: The rate at which the velocity of an object changes is the acceleration of the object. It is to be noted that the velocity decreases when there is deceleration. Deceleration is equal to acceleration but they differ by minus sign.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

