On a given condition the equilibrium concentration of$HI$ , ${H_2}$ and ${I_2}$ are 0.80, 0.10 and 0.10 $mole\,litr{e^{ - 1}}$ . The equilibrium constant for the reaction
${H_2} + {I_2} \rightleftharpoons 2HI$ will be:
(A) 64
(B) 36
(C) 8
(D) 6
Answer
632.7k+ views
Hint:In order to this question, if the equilibrium concentration and the equilibrium reaction is given, then we can find the expression for the equilibrium constant by the formula which is totally dependent on the concentration.
Complete step-by-step solution:First, we will discuss equilibrium reactions, equilibrium concentration and equilibrium constant, then after we will solve the numerical related to equilibrium.
Chemical equilibrium reaction refers to the state of a system in which the concentration of the reactant and the concentration of the products do not change with time and the system does not display any further change in properties.
Equilibrium concentration is a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction. At the same time, there is no change in the products and reactants, and it seems that the reaction has stopped. Image will be uploaded soon.
Given:-
The equilibrium reaction is ${H_2} + {I_2} \rightleftharpoons 2HI$
A chemical reaction between the reactants that stays in a stable state before and after the completion of the reaction.
The equilibrium concentrations are given below:
$[HI] = 0.18$ ,
$[{H_2}] = 0.10$
$[{I_2}] = 0.10$
The equilibrium constant is the value of the reaction quotient that is calculated from the expression for chemical equilibrium. It depends on the ionic strength and temperature and is independent of the concentrations of reactants and products in a solution.
Now, Let’s find the expression for the equilibrium constant , ${K_c}$ , symbol of equilibrium constant.
$\therefore $ The expression for the equilibrium constant is:
${K_c} = \dfrac{{{{[HI]}^2}}}{{[{H_2}][{I_2}]}} = \dfrac{{0.80 \times 0.80}}{{0.10 \times 0.10}} = 64$
So, the equilibrium constant for the given reactions is 64.
Hence, the correct option is (A) 64.
Note:Equilibrium is chiefly a thermodynamic property. However, this only tells us how far left or right the reaction is. It does not tell how fast the reaction goes to achieve that. It is also used to measure the volume of one reagent required to react with a measured mass or volume of another reagent.
Complete step-by-step solution:First, we will discuss equilibrium reactions, equilibrium concentration and equilibrium constant, then after we will solve the numerical related to equilibrium.
Chemical equilibrium reaction refers to the state of a system in which the concentration of the reactant and the concentration of the products do not change with time and the system does not display any further change in properties.
Equilibrium concentration is a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction. At the same time, there is no change in the products and reactants, and it seems that the reaction has stopped. Image will be uploaded soon.
Given:-
The equilibrium reaction is ${H_2} + {I_2} \rightleftharpoons 2HI$
A chemical reaction between the reactants that stays in a stable state before and after the completion of the reaction.
The equilibrium concentrations are given below:
$[HI] = 0.18$ ,
$[{H_2}] = 0.10$
$[{I_2}] = 0.10$
The equilibrium constant is the value of the reaction quotient that is calculated from the expression for chemical equilibrium. It depends on the ionic strength and temperature and is independent of the concentrations of reactants and products in a solution.
Now, Let’s find the expression for the equilibrium constant , ${K_c}$ , symbol of equilibrium constant.
$\therefore $ The expression for the equilibrium constant is:
${K_c} = \dfrac{{{{[HI]}^2}}}{{[{H_2}][{I_2}]}} = \dfrac{{0.80 \times 0.80}}{{0.10 \times 0.10}} = 64$
So, the equilibrium constant for the given reactions is 64.
Hence, the correct option is (A) 64.
Note:Equilibrium is chiefly a thermodynamic property. However, this only tells us how far left or right the reaction is. It does not tell how fast the reaction goes to achieve that. It is also used to measure the volume of one reagent required to react with a measured mass or volume of another reagent.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

